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a) \(\left(x-7\right)-\left(5-x\right)=12-\left(-8+x\right)\)
\(\Leftrightarrow x-7-5+x=12+8-x\)
\(\Leftrightarrow2x-12=20-x\)
\(\Leftrightarrow2x+x=12+20\)
\(\Leftrightarrow3x=32\)
\(\Leftrightarrow x=\frac{32}{3}\)
b) 124 + ( 13 - 16 ) = 162 - ( x + 162 )
<=> 124 - 3 = 162 - x - 162
<=> 121 = -x
<=> x = -121
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124 + |13 + x|*2 = 162
=> |13 + x|*2 = 38
=> |13 + x| = 19
=> 13 + x = 19 hoặc 13 + x = -19
=> x = 6 hoặc x = -32
vậy_
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mn giải đáp án ra giúp mik nha,mik cảm ơn nhiều!Thank you!
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\(a\)\(3^{39}\)và \(11^{21}\)
\(3^{39}< 11^{21}\)vì
\(3^{39}< 3^{40}=3^{39}< \left(3^2\right)^{20}=9^{20}< 11^{21}\)
\(\Rightarrow3^{39}< 11^{29}\)
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a, 339 < 340 = (32)20=920<1121
b, chép đúng đề bài ko pn
c, 1340< 1640= (24)40= 2160<2162
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339 < 340 = (32)20=920<1121
677>162
1340< 1640= (24)40= 2160<2162
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a) \(3^x\cdot3=243\)
\(\Rightarrow3^{x+1}=243\)
\(\Rightarrow3^{x+1}=3^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
b) \(2^x\cdot162=1024\)
Xem lại đề
c) \(64\cdot4^x=168\)
Xem lại đề
d) \(2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
a: =>3^x=81
=>x=4
b: =>2^x=1024/16^2=4
=>x=2
c: =>4^x=16^8/64=4^16/4^3=4^13
=>x=13
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mình giải ý c
5(x+27)=200
(x+27)=200:5
(x+27)=40
x=40-27
x=13
\(124+\left(13-16\right)=162-\left(x+162\right).\)
\(124+13-16=162-\left(x+162\right)\)
\(121=162-\left(x+162\right)\)
\(41=x+162\)
\(x=41-162=\left(-121\right)\)
124 + ( 13 – 16 ) = 162 – ( x + 162 )
124 + (-3) = 162 - ( x + 162 )
121 = 162 - ( x + 162 )
\(\Rightarrow\)162 - ( x + 162 ) = 121
162 - x - 162 = 121
( 162 - 162 ) - x = 121
0 - x = 121
- x = 121
\(\Rightarrow\) x = -121