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24 tháng 9 2021

bó tay luôn

 

22 tháng 7 2023

a) \(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{4}{3}+\dfrac{3}{4}\)

\(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{25}{12}\)

\(\dfrac{1}{2}:y=\dfrac{25}{12}:\dfrac{3}{5}\)

\(\dfrac{1}{2}:y=\dfrac{125}{36}\)

\(y=\dfrac{1}{2}:\dfrac{125}{36}\)

\(y=\dfrac{18}{125}\)

b) \(\dfrac{4}{3}-\dfrac{1}{2}\times y=1\)

\(\dfrac{1}{2}\times y=\dfrac{4}{3}-1\)

\(\dfrac{1}{2}\times y=\dfrac{1}{3}\)

\(y=\dfrac{1}{3}:\dfrac{1}{2}\)

\(y=\dfrac{2}{3}\)

c) \(\dfrac{1}{4}+y:\dfrac{1}{3}=\dfrac{5}{6}\)

\(y:\dfrac{1}{3}=\dfrac{5}{6}-\dfrac{1}{4}\)

\(y:\dfrac{1}{3}=\dfrac{7}{12}\)

\(y=\dfrac{7}{12}\cdot\dfrac{1}{3}\)

\(y=\dfrac{7}{36}\)

AH
Akai Haruma
Giáo viên
24 tháng 9 2021

Bài 1:

a. 

$\frac{2}{3}\times \frac{x}{y}=\frac{8}{15}$

$\frac{x}{y}=\frac{8}{15}: \frac{2}{3}=\frac{4}{5}$

b.

$\frac{x}{y}: \frac{3}{4}=\frac{2}{5}$

$\frac{x}{y}=\frac{3}{4}\times \frac{2}{5}=\frac{3}{10}$

c.

$\frac{3}{5}: \frac{x}{y}=\frac{4}{7}$

$\frac{x}{y}=\frac{3}{5}: \frac{4}{7}=\frac{21}{20}$

AH
Akai Haruma
Giáo viên
24 tháng 9 2021

Bài 2:

Chiều dài hình chữ nhật là:

$\frac{3}{5}: \frac{3}{4}=\frac{4}{5}$ (m)

Chu vi hình chữ nhật:

$2\times (\frac{3}{4}+\frac{4}{5})=\frac{31}{10}$ (m)

17 tháng 9 2023

\(a,y+\dfrac{2}{3}=\dfrac{5}{2}\)

\(y=\dfrac{5}{2}-\dfrac{2}{3}\)

\(y=\dfrac{15}{6}-\dfrac{4}{6}\)

\(y=\dfrac{11}{6}\)

\(b,3\dfrac{4}{5}-y=\dfrac{18}{5}\)

\(y=3\dfrac{4}{5}-\dfrac{18}{5}\)

\(y=\dfrac{19}{5}-\dfrac{18}{5}\)

\(y=\dfrac{1}{5}\)

\(c,y-4\dfrac{5}{6}=2\dfrac{1}{6}+\dfrac{5}{6}\)

\(y-\dfrac{29}{6}=\dfrac{13}{6}+\dfrac{5}{6}\)

\(y-\dfrac{29}{6}=\dfrac{18}{6}\)

\(y=\dfrac{18}{6}+\dfrac{29}{6}\)

\(y=\dfrac{47}{6}\)

28 tháng 11 2018

may bai nay de ma ban tu lam di

18 tháng 7 2023

Bài 4:

\(\dfrac{3}{4}+y:\dfrac{2}{5}=\dfrac{37}{16}\)

\(\Rightarrow y:\dfrac{2}{5}=\dfrac{37}{16}-\dfrac{3}{4}\)

\(\Rightarrow y:\dfrac{2}{5}=\dfrac{25}{16}\)

\(\Rightarrow y=\dfrac{2}{5}\cdot\dfrac{25}{16}\)

\(\Rightarrow y=\dfrac{5}{8}\)

________________

\(456+y:87=23987\)

\(\Rightarrow y:87=23987-456\)

\(\Rightarrow y:87=23531\)

\(\Rightarrow y=23531\cdot87\)

\(\Rightarrow y=2047197\)

a)\(\dfrac{4}{5}\times\dfrac{5}{8}:\dfrac{4}{5}\)

\(=\left(\dfrac{4}{5}:\dfrac{4}{5}\right)\times\dfrac{5}{8}\)

\(=1\times\dfrac{5}{8}=\dfrac{5}{8}\)

b)\(\dfrac{5}{6}+\left(\dfrac{1}{2}:\dfrac{3}{2}+\dfrac{4}{5}\right)\)

\(=\dfrac{5}{6}+\left(\dfrac{1}{3}+\dfrac{4}{5}\right)\)

\(=\dfrac{5}{6}+\dfrac{17}{15}\)

\(=\dfrac{59}{30}\)

Bài 2:

a) \(\dfrac{3}{4}+y:\dfrac{2}{5}=\dfrac{37}{16}\)

\(y:\dfrac{2}{5}=\dfrac{37}{16}-\dfrac{3}{4}\)

\(y:\dfrac{2}{5}=\dfrac{25}{16}\)

\(y=\dfrac{25}{16}\times\dfrac{2}{5}\)

\(y=\dfrac{5}{8}\)

b)\(456+y:87=23987\)

\(y:87=23987-456\)

\(y:87=23531\)

\(y=23531\times87\)

\(y=2047197\)