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\(3^{x+4}+3^{x+2}=270\)
\(\Leftrightarrow3^x\cdot90=270\)
hay x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
3x+1 + 3x+2 - 2 x 3x = 270
3x ( 3 + 32 - 2) = 270
3x . 10 = 270
3x = 270 : 10
3x = 27
3x = 33
x = 3
\(3^{x+1}+3^{x+2}-2.3^x=270\)
\(\Leftrightarrow3.3^x+3^2.3^x-2.3^x=270\)
\(\Leftrightarrow\left(3+3^2-2\right).3^x=270\)
\(\Leftrightarrow10.3^x=270\)
\(\Leftrightarrow3^x=27\)
\(\Leftrightarrow3^x=3^3\)
\(\Leftrightarrow x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a.\(2^x-2^4.2^7.32=0\)
\(2^x-2^{16}=0\)
\(=>x=16\)
b.\(3^x+3^{x+2}=270\)
\(3^x+3^x.3^2=270\)
\(3^x.10=270\)
\(3^x=27\)
\(=>x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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a: \(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=2\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 1245 - 3x = 735
3x = 1245 - 735
3x = 510
x = 510 : 3
x = 170
b) 14x - 8x + 34 = 94
6x + 34 = 94
6x = 94 - 34
6x = 60
x = 60 : 6
x = 10
c) 3x+2 + 3x = 270
3x . 32 + 3x . 1 = 270
3x . ( 32 + 1 ) = 270
3x . 10 = 270
3x = 270 : 10
3x = 27
3x = 33
=> x = 3
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 1245 - 3x = 735
3x = 1245 - 735
3x = 510
x = 510 : 3
x = 170
b,14x - 8x + 34 = 94
14x - 8x =94-34
14x - 8x =60
x(14-8) = 60
x.6 =60
x =60 :6
x =10
![](https://rs.olm.vn/images/avt/0.png?1311)
Em kiểm tra lại đề bài, \(3^x+3^{x+2}+3^{x+2}\) hay \(3^x+3^{x+1}+3^{x+2}\)
3^x+2 + 3^x = 270
3^x . 9 + 3^x = 270
3^x ( 1+9)= 270
3^x . 10 = 270
3^x = 27
3^x = 3^3
=> x= 3
Ta có: 3x+2+3x=270
=>3x.(32+1)=270
=>3x.10=270
=>3x=27=33
=>x=3