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\(\dfrac{9^{14}\cdot25^5\cdot8^7}{18^2\cdot625^3\cdot24^3}\)
\(=\dfrac{3^{42}\cdot5^{10}\cdot2^{21}}{2^2\cdot3^4\cdot5^{12}\cdot2^9\cdot3^3}=\dfrac{3^{42}\cdot5^{10}\cdot2^{21}}{2^{11}\cdot3^7\cdot5^{12}}\)
\(=\dfrac{3^{35}}{5^2}\cdot2^{10}\)
\(a,\)\(\frac{2^5\times3^{12}\times7^8}{2^7\times3^{10}\times7^9}=\frac{3^2\times\left(2^5\times3^{10}\times7^8\right)}{2^2\times7\times\left(2^5\times3^{10}\times7^8\right)}\)\(=\frac{3^2}{2^2\times7}=\frac{9}{28}\)
\(b,\)Tương tự
a 25 phần 41
b 9
c 1 phần 12
d 12
e 14 phần 15
f 24 phần 7
\(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{11}+9.5^{11}.7^{11}}\)
\(=\frac{5^{11}.7^{11}.7^1+5^{11}.7^{11}}{5^{11}.5^1.7^{11}+3^2.5^{11}.7^{11}}\)
\(=\frac{5^{11}.\left(7^{11}+7^{11}\right).7^1}{5^{11}.\left(7^{11}+7^{11}\right).5^1.3^2}\)
\(=\frac{7}{5.3^2}\)
\(=\frac{7}{45}\)
\(A=\frac{9}{7}\times\frac{13}{5}\times\frac{9}{4}=\frac{1053}{140}\)
\(B=\frac{27}{5}\times\frac{13}{7}\times\frac{1}{4}=\frac{351}{140}\)
Vậy \(\frac{A}{B}=A:B=\frac{1053}{140}:\frac{351}{140}=\frac{1053}{351}=3\)
1: \(\dfrac{-7}{4}\cdot\dfrac{2}{9}=\dfrac{-14}{36}=\dfrac{-7}{18}\)
2: \(=\dfrac{12}{13}\cdot\dfrac{26}{5}=\dfrac{24}{5}\)
3: \(=\dfrac{20}{11}\cdot\dfrac{55}{21}=\dfrac{100}{21}\)
4: \(=\dfrac{-40}{240}=\dfrac{-1}{6}\)
4/7/9*32=128/7/9=1152/7
\(\frac{4.7}{9.32}\)=\(\frac{1.7}{9.8}\)=\(\frac{7}{72}\)
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