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1) \(6x+3=0\Leftrightarrow6x=-3\Leftrightarrow x=-\dfrac{1}{2}\)
2) \(-5x-7=0\Leftrightarrow-5x=7\Leftrightarrow x=-\dfrac{7}{5}\)
3) \(\left(3x-2\right)\left(5-x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-2=0\\5-x=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=5\end{matrix}\right.\)
4) \(x^2-3x=0\Leftrightarrow x\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
6) \(x^4+8=0\)( vô lý do \(x^4+8\ge8>0\))
Vậy \(S=\varnothing\)
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neu bot mot canh hinnh vuong di 7 m va bot mot canh khac di 25 m thi duoc mot hinh chu nhat co chieu dai gap 3 lan chieu rong tinh chu vi va dien h hinh vuong
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c) \(\left|x\right|=3,5\Rightarrow\left[{}\begin{matrix}x=3,5\\x=-3,5\end{matrix}\right.\)
d) \(\left|x\right|=-2,7\Rightarrow x\in\varnothing\)
l) \(\left|x+\dfrac{3}{4}\right|-5=-2\Rightarrow\left|x+\dfrac{3}{4}\right|=3\)
\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=3\\x+\dfrac{3}{4}=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3-\dfrac{3}{4}\\x=-3-\dfrac{3}{4}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\\x=\dfrac{15}{4}\end{matrix}\right.\)
Đính chính câu l \(x=-\dfrac{15}{4}\) không phải \(x=\dfrac{15}{4}\)
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Vì: \(\left(x-1\right)^{26}\ge0\forall x\)
\(\left(3+x\right)^{22}\ge0\forall x\)
=>\(\left(x-1\right)^{26}+\left(3+x\right)^{22}\ge0\forall x\)
Mà: \(\left(x-1\right)^{26}+\left(3+x\right)^{22}=0\)
\(\Rightarrow\orbr{\begin{cases}\left(x-1\right)^{26}=0\\\left(3+x\right)^{22}=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}\Rightarrow}}\) ko cs giá trị thỏa mãn
=.= hok tốt!!
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