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a) 1024 9 = ( 2 10 ) 9 = 2 90 < 2 100
b) 6 . 5 29 > 5 . 5 29 = 5 30
c) 10 30 = ( 10 3 ) 10 = 1000 10 ; 2 100 = ( 2 10 ) 10 = 1024 10 n ê n 10 30 < 2 100 .
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Cách 1: 2 100 = 2 10 10 = 1024 10 > 1024 9
Cách 2: 1024 9 = 2 10 9 = 2 90 < 2 100
b) 6 . 5 29 > 5 . 5 29 = 5 30
c) 2 98 = 2 2 49 = 4 49 < 9 49
d) 10 30 = 10 3 10 = 1000 10 ; 2 100 = 2 10 10 = 1024 10 nên 10 30 < 2 100
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\(70-5\cdot\left(x-3\right)=45\)
\(\Rightarrow5\cdot\left(x-3\right)=70-45\)
\(\Rightarrow5\cdot\left(x-3\right)=25\)
\(\Rightarrow x-3=\dfrac{25}{5}\)
\(\Rightarrow x-3=5\)
\(\Rightarrow x=5+3=8\)
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\(10+2\cdot x=4^5:4^3\)
\(\Rightarrow10+2\cdot x=4^2\)
\(\Rightarrow10+2\cdot x=16\)
\(\Rightarrow2\cdot x=16-10\)
\(\Rightarrow2\cdot x=6\)
\(\Rightarrow x=\dfrac{6}{2}=3\)
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\(2\cdot x-138=2^3\cdot3^2\)
\(\Rightarrow2\cdot x-138=72\)
\(\Rightarrow2\cdot x=72+138\)
\(\Rightarrow2\cdot x=210\)
\(\Rightarrow x=\dfrac{210}{2}=105\)
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\(231-\left(x-6\right)=1339:12\)
\(\Rightarrow231-x+6=1339:12\)
\(\Rightarrow237-x=\dfrac{1339}{12}\)
\(\Rightarrow x=237-\dfrac{1339}{12}\)
\(\Rightarrow x=\dfrac{1505}{12}\)
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a: 43/52>26/52=1/2=60/120
b: 17/68=1/4<1/3=35/105<35/103
c: \(\dfrac{2018\cdot2019-1}{2018\cdot2019}=1-\dfrac{1}{2018\cdot2019}\)
\(\dfrac{2019\cdot2020-1}{2019\cdot2020}=1-\dfrac{1}{2019\cdot2020}\)
2018*2019<2019*2020
=>-1/2018*2019<-1/2019*2020
=>\(\dfrac{2018\cdot2019-1}{2018\cdot2019}< \dfrac{2019\cdot2020-1}{2019\cdot2020}\)
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\(\dfrac{19}{19}\) = 1 < \(\dfrac{2005}{2004}\) vậy \(\dfrac{19}{19}\) < \(\dfrac{2005}{2004}\)
\(\dfrac{72}{73}\) = 1 - \(\dfrac{1}{73}\)
\(\dfrac{98}{99}\) = 1 - \(\dfrac{1}{99}\)
Vì \(\dfrac{1}{73}\) > \(\dfrac{1}{99}\) nên \(\dfrac{72}{73}\) < \(\dfrac{98}{99}\)
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a) ta có: \(1-\frac{2012}{2013}=\frac{1}{2013}\)
\(1-\frac{2013}{2014}=\frac{1}{2014}\)
mà \(\frac{1}{2013}>\frac{1}{2014}\) nên \(\frac{2013}{2014}>\frac{2012}{2013}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2225 = (23)75 = 875
3151 > 3150 = (32)75 = 975
=> 3151 > 975 > 875
=> 3151 > 2225
4n - 5 chia hết cho 2n - 1
=> 4n - 2 - 3 chia hết cho 2n - 1
=> 2.(2n - 1) - 3 chia hết cho 2n - 1
Do 2.(2n - 1) chia hết cho 2n - 1 => 3 chia hết cho 2n - 1
Mà n thuộc N => 2n - 1 > hoặc = -1
=> 2n - 1 thuộc {-1 ; 1 ; 3}
=> 2n thuộc {0 ; 2 ; 4}
=> n thuộc {0 ; 1 ; 2}
ta có \(45^{10}.5^{30}=9^{10}.5^{10}.5^{30}=9^{10}.5^{40}=3^{20}.25^{20}=75^{20}\)
vậy \(75^{20}=45^{10}.5^{30}\)
~ CHÚC BN HOK TỐT ~ chỗ nào ko hiểu hỏi lại mik