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`@` `\text {Ans}`
`\downarrow`
\(1793\cdot\left(x\div1792\right)=0\)
`\Rightarrow x \div 1792 = 0 \div 1793`
`\Rightarrow x \div 1792 = 0`
`\Rightarrow x = 0. 1792`
`\Rightarrow x = 0`
Vậy, `x = 0.`
\(1793.\left(x:1792\right)=0\)
\(=>x:1792=0:1793\)
\(=>x:1792=0\)
\(=>x=0.1792\)
\(=>x=0\)
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a, 190 - 2(2x-6) = 182
=> 2 ( 2x - 6 ) = 8
=> 2x - 6 = 4
=> 2x = 10
=> x = 5
b, 1300 : [ 120 - ( x - 9 ) ] = 25
=> [ 120 -( x - 9 ) ] = 52
=> x - 9 = 68
=> x = 77
c, 1793 ( x : 1792 ) = 0
=> x : 1972 = 0
=> x = 0
a)
190-2(2x-6)=182
2(2x-6)=190-182
2(2x-6)=8
2x-6=8:2
2x-6=4
2x=4-6
2x=-2
x=-2:2
x=-1
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=> 1 - (43/8+x-173/24) = 0
=> 43/8 + x - 173/24 = 1
=> 43/8 + x = 197/24
=> x = 17/6
k nha
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a) \(\frac{1}{3}x+\frac{2}{5}x+\frac{2}{5}=0\Leftrightarrow\frac{11}{15}x=-\frac{2}{5}\Leftrightarrow x=-\frac{6}{11}\)
b) \(\Leftrightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right).-\frac{3}{50}=1\Leftrightarrow\frac{-11}{6}+x=-\frac{50}{3}\Leftrightarrow x=-\frac{37}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(123-\left(x+345\right)-2x=1792\)
\(\Leftrightarrow123-x-345-2x=1792\)
\(\Rightarrow-222-3x=1792\)
\(\Leftrightarrow-3x=1792+\left(-222\right)\)
\(\Leftrightarrow-3x=1570\)
\(\Rightarrow x=\frac{-1570}{3}\)
123 – (x + 345) – 2x = 1792
123 – x – 345 – 2x = 1792
–222 – 3x = 1792
–3x = 1792 + 222
–3x = 2014
=> x = – 2014/3
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (3x-12) :8 +10= 13
<=> (3x-12):8 = 13-10 = 3
<=> 3x-12 = 3 .8 = 24
<=> 3x = 24+12=36
<=> x=36:3=12
b) (x+5).8-20 = 60
<=> (x+5) .8 = 60+20=80
<=> x+5 = 80:8 = 10
<=> x=10-5 = 5
c) 3.[35+(x-10)]-375 = 0
<=> 3.[35+(x-10)] = 0 +375=375
<=> 35+(x-10) = 375 :3 = 125
<=> x-10 = 125-35=90
<=> x = 90+10 = 100
d) ( 158x+173-24) :35 = 81
<=> 158x+149 = 81 . 35 = 2835
<=> 158x = 2835 -149= 2686
<=> x= 2686 : 158 = 17
e) x - 140 : 35 = 0
<=> x-4 = 0
<=> x=0+4 = 4
(3x - 12 ) : 8 + 10 = 13
(3x - 12 ) : 8 = 13 - 10 = 3
(3x - 12 ) = 3 x 8 = 24
3x = 24 - 12 = 12
x =13 : 3 = 4
( x + 5 )
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-15\right)^7=0\Rightarrow3x-15=0\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
\(4^2.x-6=1\Rightarrow16.x=7\)
\(\Rightarrow x=\frac{7}{16}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(173\times\left(x:1792\right)=0\)
\(\Rightarrow x:1792=0:173\)
\(\Rightarrow x:1792=0\)
\(\Rightarrow x=0\times1792\)
\(\Rightarrow x=0\)
Vậy x = 0
_Chúc bạn học tốt_
suy ra x.1792=0
suy ra x=0