![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.x=\frac{3}{4}-\frac{1}{2}=\frac{1}{4}\)
\(b.x=\frac{4}{7}:\frac{4}{5}=\frac{5}{7}\)
\(c.8x-7,8x=25\)
\(0,2x=25\Rightarrow x=125\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2x - 138 = 23 . 32
=> 2x - 138 = 72
=> 2x = 72 + 138
=> 2x = 210
=> x = 105
10 + 2x = 43 . 42
10 + 2x =1024
2x = 1024 - 10
2x = 1014
x = 507
(3x - 24) . 73 = 2.74
3x - 24 = 2 . 74 : 73
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 10
x4 = 16
=> x4 = 24
=> x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+\frac{2}{15}=\frac{1}{3}\)
\(x=\frac{1}{3}-\frac{2}{15}\)
\(x=\frac{1}{5}\)
h, \(h,\frac{1}{3}-\frac{2}{3}:x=\frac{1}{4}\)
\(\frac{2}{3}:x\)= \(\frac{1}{3}-\frac{1}{4}\)
\(\frac{2}{3}:x=\frac{1}{12}\)
\(x=\frac{2}{3}:\frac{1}{12}\)
\(x=8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(4^{x+2}+5.4^x=84\Rightarrow4^x\left(4^2+5\right)=84\Rightarrow4^x=4^1\Rightarrow x=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(169-4^2\right).\left(169-5^2\right)...\left(169-13^2\right)\)
Mà \(13^2=169\)
\(\Rightarrow\left(169-4^2\right)\left(169-5^2\right)...\left(169-169\right)\)
\(=\left(169-4^2\right)\left(169-5^2\right)...0\)
\(=0\)
1. \(\frac{4}{5}\cdot x=\frac{4}{7}\Rightarrow x=\frac{4}{7}:\frac{4}{5}=\frac{20}{28}=\frac{5}{7}\)
Vậy \(x=\frac{5}{7}\)
2.\(8x=7,8x+25\Rightarrow8x=\frac{39}{5}x+25=1000\)
\(1000:8=125\)và \(\left(1000-25\right):\frac{39}{5}=125\)
\(\Rightarrow x=125\)