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a) \(\frac{3}{5}\times y+\frac{1}{2}:\frac{5}{3}-\frac{5}{4}=\frac{1}{2}\times\frac{1}{3}\)
\(\Rightarrow\frac{3}{5}\times y+\frac{3}{10}-\frac{5}{4}=\frac{1}{6}\)
\(\Rightarrow\frac{3}{5}\times y+\left(-\frac{19}{20}\right)=\frac{1}{6}\)
\(\Rightarrow\frac{3}{5}\times y=\frac{67}{60}\)
\(\Rightarrow y=\frac{67}{36}\)
b) \(\frac{4}{5}:y+\frac{1}{4}\times\frac{1}{6}-\frac{1}{2}=\frac{1}{3}\times\frac{5}{2}\)
\(\Rightarrow\frac{4}{5}:y+\frac{1}{24}-\frac{1}{2}=\frac{5}{6}\)
\(\Rightarrow\frac{4}{5}:y+\left(-\frac{11}{24}\right)=\frac{5}{6}\)
\(\Rightarrow\frac{4}{5}:y=\frac{5}{6}+\frac{11}{24}=\frac{31}{24}\)
\(\Rightarrow y=\frac{4}{5}:\frac{31}{24}=\frac{96}{155}\)
c) \(\frac{3}{5}\times y-\frac{4}{5}:3+\frac{1}{12}=\frac{3}{2}+\frac{1}{5}\)
\(\Rightarrow\frac{3}{5}\times y-\frac{4}{15}+\frac{1}{12}=\frac{17}{10}\)
\(\Rightarrow\frac{3}{5}\times y-\frac{4}{15}=\frac{97}{60}\)
\(\Rightarrow\frac{3}{5}\times y=\frac{113}{60}\)
\(\Rightarrow y=\frac{113}{36}\)
\(y+3\frac{1}{2}=3\frac{2}{4}\)
\(y=3\frac{2}{4}-3\frac{1}{2}\)
\(y=\frac{0}{4}\)
a) \(\frac{27}{36}=\frac{3}{4}\)
b) \(\frac{45}{60}=\frac{3}{4}\)
c) \(\frac{2}{4}=\frac{1}{2}\)
d) \(\frac{10}{12}=\frac{5}{6}\)
e) \(\frac{112}{252}=\frac{4}{9}\)
Đúng nha bạn !!@@
\(\frac{1}{3}+\frac{3}{4}x\frac{5}{9}=\frac{1}{3}+\frac{5}{12}=\frac{3}{4}\)
\(\frac{7}{12}-\frac{5}{4}x\frac{2}{15}=\frac{7}{12}-\frac{1}{6}=\frac{5}{12}\)
\(y+\frac{1}{4}=\frac{7}{8}-\frac{3}{8}=y+\frac{1}{4}=\frac{1}{2}=\frac{1}{2}-\frac{1}{4}=\frac{1}{4}\)
\(y-\frac{5}{12}=\frac{2}{3}-\frac{1}{4}=y-\frac{5}{12}=\frac{5}{12}=\frac{5}{12}+\frac{5}{12}=\frac{5}{6}\)
\(\frac{12}{7}xy=\frac{16}{21}=\frac{16}{21}:\frac{12}{7}=\frac{4}{9}\)
\(\frac{5}{4}:y=\frac{7}{12}=\frac{5}{4}:\frac{7}{12}=\frac{15}{7}\)
a) $\frac{1}{4} + ..... = \frac{3}{4}$
$\frac{3}{4} - \frac{1}{4} = \frac{1}{2}$
Vậy phân số cần tìm là $\frac{1}{2}$
b) $..... - \frac{3}{5} = \frac{1}{5}$
$\frac{1}{5} + \frac{3}{5} = \frac{4}{5}$
Vậy phân số cần tìm là $\frac{4}{5}$
c) $\frac{2}{3} - ...... = \frac{1}{3}$
$\frac{2}{3} - \frac{1}{3} = \frac{1}{3}$
Vậy phân số cần tìm là $\frac{1}{3}$
\(\Rightarrow2+\frac{3}{\frac{7-4y}{2-y}}=7\)
\(\Rightarrow\frac{3}{\frac{7-4y}{2-y}}=5\)
\(\Rightarrow3\times\frac{2-y}{7-4y}=5\)
\(\Rightarrow\frac{2-y}{7-4y}=\frac{5}{3}\Rightarrow3\left(2-y\right)=5\left(7-4y\right)\)
\(\Rightarrow6-3y=35-20y\)
\(\Rightarrow17y=29\Rightarrow y=\frac{29}{17}\)
\(y=\frac{4}{3}-\frac{1}{3072}=\frac{4096}{3072}+\frac{1}{3072}=\frac{4096+1}{3072}=\frac{4097}{3072}\)
\(y=\frac{4}{3}-\frac{1}{3072}=\frac{4096-1}{3072}=\frac{4095}{3072}=\frac{1365}{1024}\)