Question

[Thai Tran Anh]

x²=√x.tìm x

Answer 1

[Nguyễn Hoàng Minh]

ĐK: \(x\ge0\)

\(\Rightarrow x^4=x\\ \Rightarrow x^4-x=0\\ \Rightarrow x\left(x^3-1\right)=0\\ \Rightarrow x\left(x-1\right)\left(x^2+x+1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=1\\x^2+x+\dfrac{1}{4}+\dfrac{3}{4}=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=1\\\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}=0\left(vô.nghiệm\right)\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Answer 2

[Đỗ Dương Minh Khuê]