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23.27.24=23+7+4=214
23.24:25=23+4-5=27
(-3)+(-125)+(-25)
=-128+(-25)
=-153
25+(-38)=25-38=-13
126+159=285
120+(-135)+200
=120-135+200
=-15+200
=185
2^3x2^7=2^10x2^4=2^14=16384
2^3x2^4=2^7:2^5=2^2=4
1300-(150.2+(900+90):9)=1300-(150.2+990:9)=1300-(300+11)=1300-311=989
(-3) + (-125)+(-25)= -(3+125+25)= -153
25 + (-38)= -(38-25)= - 13
(126)+159=285
(120)+(-135)+200= -(135-120) + 200= (-15) + 200= +(200-15)=185
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=9x2^25-2^2x2^26/2^24x5^2-2^27x3
=9x2^25-2^28/2^24x5^2-2^27x3
=2^25x(9-2^3)/2^24x(5^2-2^3x3)
=2^25/2^24
=2^1=2
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a) \(9.x-2.x=\frac{6^{27}}{6^{25}}+\frac{48}{12}\)
\(\Leftrightarrow7x=6^2+4\)
\(\Leftrightarrow7x=36+4=40\)
\(\Leftrightarrow x=\frac{40}{7}\)
Vậy : \(x=\frac{40}{7}\)
b) \(11^x=5.x+\frac{5^{31}}{5^{29}}+3.2^2-10^0\)
\(\Leftrightarrow11^x=5x+5^2+12-1\)
\(\Leftrightarrow11^x=5x+36\)
\(\Rightarrow x\in\varnothing\)
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\(\left(x+1\right)^3=27\)
\(\left(x+1\right)^3=3^3\)
\(\Rightarrow x+1=3\)
\(x=2\)
\(\left(x+1\right)^3=27\)
\(< =>\left(x+1\right)^3=3.3.3=3^3\)
\(< =>x+1=3< =>x=3-1=2\)
\(\left(2x+3\right)^3=9.81\)
\(< =>\left(2x+3\right)^3=9.9.9\)
\(< =>\left(2x+3\right)^3=9^3\)
\(< =>2x+3=9< =>2x=6\)
\(< =>x=\frac{6}{2}=3\)
\(\left(x+\frac{2}{3}\right)^2=\frac{25}{9}=\left(\frac{5}{4}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{2}{3}=\frac{5}{4}\\x+\frac{2}{3}=\frac{-5}{4}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{5}{4}-\frac{2}{3}=\frac{7}{12}\\x=\frac{-5}{4}-\frac{2}{3}=\frac{-23}{12}\end{cases}}\)
\(\left(x+\frac{2}{3}\right)^2=\frac{25}{9}=\left(\frac{5}{4}\right)^2\)
\(\Leftrightarrow x+\frac{2}{3}=\frac{5}{4}\Leftrightarrow x=\frac{5}{4}-\frac{2}{3}=\frac{15-8}{12}=\frac{7}{12}\)
Vậy \(x=\frac{7}{12}\)