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Thiếu vế phải rồi, mình biến đổi vế trái ra nhé
Ta có: \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)\)
\(=\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)\)
\(=100x+\frac{\left(1+100\right)\cdot\left[\left(100-1\right)\div1+1\right]}{2}\)
\(=100x+5050\)
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(x + 1) + (x + 2) + (x + 3) +...+ (x + 100) = 5750
x + 1 + x + 2+ x + 3 + ... + x + 100 = 5750
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5750
100x + \(\frac{100.101}{2}\)= 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700 <=> x = 7
Vậy x = 7
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D=1x2x3 + 3x4x5 + ... + 99x100x101 đề chính xác là như vậy ah bn?
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\(\dfrac{5}{7}x-x=1\dfrac{1}{7}\\ < =>\dfrac{5}{7}x-x=\dfrac{8}{7}\\ < =>\left(\dfrac{5}{7}-\dfrac{7}{7}\right)x=\dfrac{8}{7}\\ < =>-\dfrac{2}{7}x=\dfrac{8}{7}\\ =>x=\dfrac{\dfrac{8}{7}}{-\dfrac{2}{7}}=-4\)
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5(x+4)-3(x-2)=x
\(\Leftrightarrow5x+20-3x+6=x\)
\(\Leftrightarrow2x+26=x\)
\(\Leftrightarrow2x-x=-26\)
\(x=-26\)
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Trl: (Tìm x)
a) \(4x-7=3x-\left(-5\right)\)
\(4x-7=3x+5\)
\(4x-3x=5+7\)
\(x=12\)
Vậy \(x=12\)
b) \(3\left(x-1\right)=-x-12\)
\(3x-3=-x-12\)
\(3x+x=-12+3\)
\(4x=-9\)
\(\Rightarrow x=\frac{-4}{9}\)
Vậy \(x=\frac{-4}{9}\)
#HuyenAnh
(x+1)+(x+2)+(x+3)+...+(x+100)=9050
(x+x+x+...+x)+(1+2+3+...+100)=9050
x*100+(100+1)*100:2=9050
x*100+101*50=9050
x*100+5050=9050
x*100=9050-5050
x*100=4000
x =4000:100
x =40
(k cho mk nhé!!!)
(x + 1 ) + (x + 2) + (x + 3) + ... + (x + 100) = 9050
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 9050
(x . 100) + (1 + 100 ) . 100 : 2 = 9050
x . 100 + 5050 = 9050
x .100 = 9050 - 5050
x . 100 = 4000
x = 4000 : 100
x = 40
Vậy x = 40
Học tốt!!!