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X : 6 x 7,2 + X x 1,3 + X : 2 + 15 = 19,95
X x \(\frac{1}{6}\) x \(\frac{36}{5}\)+ X x \(\frac{13}{10}\)+ X x \(\frac{1}{2}\) = 19,95 - 15 = 4,95 = \(\frac{99}{20}\)
X x \(\frac{6}{5}\)+ X x \(\frac{13}{10}\)+ X x \(\frac{1}{2}\)= \(\frac{99}{20}\)
X x ( \(\frac{6}{5}+\frac{13}{10}+\frac{1}{2}\)) = \(\frac{99}{20}\)
X x 3 = \(\frac{99}{20}\)
X = \(\frac{99}{20}:3\)
X = \(\frac{33}{20}\)
X : 6 x 7,2 + 1,3 x X + X : 2 + 15 = 19,95
(X x 7,2) / 6 + (7,8 x X) / 6 + (X x 3) / 6 + 90/6 = 119,7/6
X x 7,2 + 7,8 x X + X x 3 + 90 = 119,7
X x (7,2 + 7,8 + 3) = 119,7 - 90
X x 18 = 29,7
X = 29,7 : 18
X = 1,65
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>|x+2|=2x-6
\(\Leftrightarrow\left\{{}\begin{matrix}x>=3\\\left(2x-6-x-2\right)\left(2x-6+x+2\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=3\\\left(x-8\right)\left(3x-4\right)=0\end{matrix}\right.\Leftrightarrow x=8\)
b: =>1,2x+1,3x=2,95
=>2,5x=2,95
hay x=1,18
![](https://rs.olm.vn/images/avt/0.png?1311)
a, |x + 2| + 6 = 2x
\(\Rightarrow\left|x+2\right|=2x-6\) (1)
Vì |x + 2| \(\ge\) 0 \(\Rightarrow2x-6\ge0\Rightarrow2x\ge6\Rightarrow x\ge3\)
Từ (1) \(\Rightarrow\left[{}\begin{matrix}x+2=2x-6\\x+2=-\left(2x-6\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2x=-6-2\\x+\left(-2x\right)=6-2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}3x=-8\\-x=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{8}{3}\\x=-4\end{matrix}\right.\)(Loại)
Vậy không có giá trị x thỏa mãn
![](https://rs.olm.vn/images/avt/0.png?1311)
Với mọi giá trị của \(x\in R\) ta có:
\(\left|x+1\right|\ge0;\left|x+1,2\right|\ge0;\left|x+1,3\right|\ge0;\left|x+1,4\right|\ge0\)
\(\Rightarrow\left|x+1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|\ge0\)
mà \(\left|x+1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|=5x\)
nên \(5x\ge0\Rightarrow x\ge0\)
\(\Rightarrow\left\{{}\begin{matrix}\left|x+1\right|=x+1\\\left|x+1,2\right|=x+1,2\\\left|x+1,3\right|=x+1,3\\\left|x+1,4\right|=x+1,4\end{matrix}\right.\)
\(\Rightarrow x+1+x+1,2+x+1,3+x+1,4=5x\)
\(\Rightarrow4x+4,9=5x\Rightarrow x=4,9\)
Chúc bạn học tốt!!!
\(\left|x+1\right|\ge0\) \(\left|x+1,2\right|\ge0\)
\(\left|x+1,3\right|\ge0\) \(\left|x+1,4\right|\ge0\)
\(\Leftrightarrow\left|x+1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|\ge0\)
\(\Leftrightarrow x+1+x+1,2+x=1,3+x+1,4=5x\)
\(4x+4,9=5x\)
\(\Leftrightarrow x=4,9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x - ( 3,3 + 2,4 ) = 11,6
x - 5,7 =11,6
x = 11,6 + 5,7
x = 17,3
<=>x-5,7=11,6 <=>x-4,6=1,8+2,6
<=>x =11,6+5,7=17,3 <=>x-4,6=4,4
Vậy x=17,3 <=>x =4,4+4,6=9 Vậy x=9
<=>x+1,8=15,02+0,91=15,93 <=>5.x=47-27=20
<=>x =15,93-1,8=14,13 <=>x =20:5=4
Vậy x=14,13 Vậy x=4
<=>x:3=0,312 8.x-3.x=1,95
<=>x =0,312.3 x.5 =1,95
<=>x =0,931 x =1,95:5
Vậy x=0,936 x=0,19 vậy x=0,19
<=>x:2=2,43+8,6=11,03
<=>x =11,03.2= 22,06
Vậy x=22,06
![](https://rs.olm.vn/images/avt/0.png?1311)
a,3x-0,75=-1,2
3x=-1,2+-0,75
3x=-9/20
x=-9/20:3
x=-3/20
kl:....
b,2/3/5:(2x-1/2)=1,3
2/3/5??????
c,3/4x-5/6=7/12x-5/4
3/4x-7/12x=-5/4+5/6
9/12x-7/12x=-15/12+10/12
2/12x=-5/12
2:12x=-5/12
12x=2:-5/12
12x=-24/5
x=-24/5:12
x=-2/5
kl:....
chúc bn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
X x 1,2 + 1,3 x X + X : 2 + 1,95 = 19,95
2X x ( 1,2 + 1,3 ) + X x 0,5 + 1,95 = 19,95
2X x 1,5 + X x 0,5 + 1,95 = 19,95
3X x ( 1,5 + 0,5 ) + 1,95 = 19,95
3X x 2 + 1,95 = 19,95
3X x 2 = 19,95 - 1,95
3X x 2 = 18
6X = 18
X = 18 : 6
X = 3
nha bạn