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\(\frac{x-3}{3}=\frac{5-3x}{-11}\)

\(\Leftrightarrow-11\left(x-3\right)=3\left(5-3x\right)\)

\(\Leftrightarrow-11x+33=15-9x\)

\(\Leftrightarrow2x=18\)

\(\Leftrightarrow x=9\)

vậy x=9

13 tháng 11 2018

a, | 5 - 3x | + \(\frac{2}{3}=\frac{1}{6}\)

=> | 5 - 3x | = \(\frac{1}{6}-\frac{2}{3}\)

=> | 5 - 3x | = \(-\frac{1}{2}\)( vô lý , vì | 5 - 3x | \(\ge\)0 )

Vậy không có giá trị của x

b, - 2,5 + | 3x + 5 | = - 1,5

=> | 3x + 5 | = - 1,5 + 2,5

=> | 3x + 5 | = 1

=> \(\orbr{\begin{cases}3x+5=1\\3x+5=-1\end{cases}\Rightarrow\orbr{\begin{cases}3x=-4\\3x=-6\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{4}{3}\\x=-2\end{cases}}}\)

Vậy x = -4 / 3 hoặc x = -2

c, \(\frac{11}{5}-\left|\frac{1}{5}-x\right|=\frac{3}{5}\)

=> \(\left|\frac{1}{5}-x\right|=\frac{11}{5}-\frac{3}{5}\)

=> \(\left|\frac{1}{5}-x\right|=\frac{8}{5}\)

=> \(\orbr{\begin{cases}\frac{1}{5}-x=\frac{8}{5}\\\frac{1}{5}-x=-\frac{8}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=-\frac{7}{5}\\x=\frac{9}{5}\end{cases}}}\)

Vậy x = - 7 / 5 hoặc x = 6 / 5

d, \(\left|x-\frac{2}{5}\right|+\frac{1}{2}=\frac{3}{4}\)

=> \(\left|x-\frac{2}{5}\right|=\frac{3}{4}-\frac{1}{2}\)

=> \(\left|x-\frac{2}{5}\right|=\frac{1}{4}\)

=> \(\orbr{\begin{cases}x-\frac{2}{5}=\frac{1}{4}\\x-\frac{2}{5}=-\frac{1}{4}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{13}{20}\\x=\frac{3}{20}\end{cases}}}\)

Vậy x = 13 / 20 hoặc x = 3 / 20

tìm x nhé!

7 tháng 8 2021

1.|x+1|+|3−2x|=|3x−2|

mà |3−2x|=|3x−2| nên |x+1|=0 => x+1=0 =>x=-1

 

 

 

a: 2x-3/2+3/4=-4

=>2x-3/4=-4

=>2x=-13/4

hay x=-13/8

b: \(\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)\cdot\left(\dfrac{-3}{2}-\dfrac{10}{3}\right)=\dfrac{2}{5}\)

\(\Leftrightarrow-\dfrac{2}{3}x-\dfrac{3}{5}=\dfrac{2}{5}:\dfrac{-29}{6}=\dfrac{-2}{5}\cdot\dfrac{6}{29}=\dfrac{-12}{145}\)

=>2/3x+3/5=12/145

=>2/3x=-15/29

hay x=-45/58

c: \(\dfrac{x}{2}-\left(\dfrac{3}{5}x-\dfrac{13}{5}\right)=-\left(\dfrac{7}{10}x+\dfrac{7}{5}\right)\)

=>1/2x-3/5x+13/5=-7/10x-7/5

=>-1/10x+7/10x=-7/5-13/5

=>3/5x=-2

hay x=-2:3/5=-10/3

1 tháng 10 2017

a. \(5.\left(x-2\right)+3.\left(x-2\right)=0\)

\(\Rightarrow8.\left(x-2\right)=0\)

\(\Rightarrow x-2=0:8\)

\(\Rightarrow x-2=0\)

\(\Rightarrow x=2\)

Vậy...

b. \(\dfrac{2}{3}+\dfrac{5}{2}:x=\dfrac{2}{4}\)

\(\Rightarrow\dfrac{5}{2}:x=\dfrac{2}{4}-\dfrac{2}{3}\)

\(\Rightarrow\dfrac{5}{2}:x=\dfrac{-1}{6}\)

\(\Rightarrow x=\dfrac{5}{2}:\dfrac{-1}{6}=-15\)

Vậy...

c. \(2.\left(x-\dfrac{1}{7}\right)=0\)

\(\Rightarrow x-\dfrac{1}{7}=0:2\)

\(\Rightarrow x-\dfrac{1}{7}=0\)

\(\Rightarrow x=\dfrac{1}{7}\)

Vậy...

d. \(\dfrac{11}{20}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)

\(\Rightarrow\dfrac{2}{5}+x=\dfrac{11}{12}:\dfrac{2}{3}\)

\(\Rightarrow\dfrac{2}{5}+x=\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{1}{4}-\dfrac{2}{5}=\dfrac{-3}{20}\)

Vậy...

e. \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)

\(\Rightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}\)

\(\Rightarrow\dfrac{1}{4}:x=\dfrac{-7}{20}\)

\(\Rightarrow x=\dfrac{1}{4}:\dfrac{-7}{20}=\dfrac{-5}{7}\)

Vậy...

g. \(\dfrac{2}{3}x+\dfrac{5}{7}=\dfrac{3}{10}\)

\(\Rightarrow\dfrac{2}{3}x=\dfrac{3}{10}-\dfrac{5}{7}\)

\(\Rightarrow\dfrac{2}{3}x=\dfrac{-29}{70}\)

\(\Rightarrow x=\dfrac{-29}{70}:\dfrac{2}{3}=\dfrac{-87}{140}\)

Vậy...

17 tháng 8 2021

a)\(\left|\dfrac{x-1}{3}\right|=\dfrac{11}{5}\Rightarrow\dfrac{x-1}{3}=\pm\dfrac{11}{5}\\ \Rightarrow\left[{}\begin{matrix}\dfrac{x-1}{3}=\dfrac{11}{5}\\\dfrac{x-1}{3}=-\dfrac{11}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x-1=\dfrac{33}{5}\\x-1=\dfrac{-33}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{38}{5}\\x=\dfrac{-28}{5}\end{matrix}\right.\)