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Mk sửa đề nha :
\(C=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{12}{7}\)
\(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)
\(=\frac{-5}{7}.1+\frac{12}{7}\)
\(=\frac{-5}{7}+\frac{12}{7}\)
\(=1\)
Study well ! >_<
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\(\frac{9^3\cdot2^{10}\cdot27^5}{4^5\cdot81^6}=\frac{3^6\cdot2^{10}\cdot3^{15}}{2^{10}\cdot3^{24}}=\frac{1}{3^3}=\frac{1}{27}\)
\(\frac{27^4\cdot2^5-3^{11}\cdot4^3}{8^2\cdot9^6}=\frac{3^{12}\cdot2^5}{2^6\cdot3^{12}}-\frac{3^{11}\cdot2^6}{2^6\cdot3^{12}}=\frac{1}{2}-\frac{1}{3}=\frac{1}{6}\)
=))
a) \(\frac{9^3.2^{10}.27^5}{4^5.81^6}\)= \(\frac{\left(3^2\right)^3.2^{10}.\left(3^3\right)^5}{\left(2^2\right)^5.\left(3^4\right)^5}\)= \(\frac{3^{2.3}.2^{10}.3^{3.5}}{2^{2.5}.3^{4.5}}\)= \(\frac{3^6.2^{10}.3^{15}}{2^{10}.3^{20}}\)= \(\frac{3^{21}.2^{10}}{2^{10}.3^{20}}\)= \(\frac{3^{20}.2^{10}.3}{2^{10}.3^{20}}\)= \(3\)
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a) \(2^6.3^3.12^2=2^{2.3}.3^3.12^2=4^3.3^3.12^2=12^3.12^2=12^5\)
b) \(20^4:2^6=\left(2^2.5\right)^4:2^6=2^8.5^4:2^6=2^2.5^4=2^2.25^2=50^2\)
c) \(100^3:2^5=\left(25.2^2\right)^3:2^5=25^3.2^6:2^5=25^3.2\)
d) \(125^2.9^3.2^6=\left(5^3\right)^2.\left(3^2\right)^3.2^6=5^6.3^6.2^6=30^6\)
e) \(81^4.9^2.3^7= \left(3^4\right)^4.\left(3^2\right)^2.3^7=3^{16}.3^4.3^7=3^{27}\)
g) \(250^6:5^5=\left(2.5^3\right)^6:5^5=2^6.5^{18}:5^6=2^6.5^{12}=50^6\)
1,26.33.24.32=210.35
2,28.54:26=22.54
3,22.52:25=\(\frac{1}{2^3}.5^2\)
4,56.92.26=106.92
5,316.34.37=327
6,518.2:55=513.2
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(3.2)^5 = 6^5 = 7776
(7.2^2)^5 = (7.4)^5 = 28^5 = 17210368
(3^2).9)^2 = (9.9)^2 = 81^2 = 6561
7776
17210368
6561
k mình nha bạn