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\(\frac{37}{35}:\frac{5}{4}:\frac{74}{25}\)
\(=\frac{37}{35}:\left(\frac{5}{4}\times\frac{74}{25}\right)\)
\(=\frac{37}{35}:\frac{37}{10}\)
\(=\frac{2}{7}\)
\(\frac{37}{35}:\frac{5}{4}:\frac{74}{25}\)
=\(\frac{37}{35}x\frac{4}{5}x\frac{25}{74}\)
\(=\left(\frac{37}{35}x\frac{25}{74}\right)x\frac{4}{5}\)
\(=\frac{1}{7}x\frac{5}{2}x\frac{4}{5}\)
\(=\frac{1x5x2x2}{7x2x5}\)
\(=\frac{2}{7}\)
\(5\dfrac{3}{4}:3+2\dfrac{1}{4}\times\dfrac{1}{3}-\dfrac{1}{8}=\left(5\dfrac{3}{4}+2\dfrac{1}{4}\right)\times\dfrac{1}{3}-\dfrac{1}{8}\\ =8\times\dfrac{1}{3}-\dfrac{1}{8}=\dfrac{8}{3}-\dfrac{1}{8}=\dfrac{61}{24}\\ ----\\ \dfrac{3}{5}:\dfrac{5}{6}:\dfrac{6}{7}:\dfrac{7}{8}+\dfrac{2}{5}+\dfrac{23}{35}\\ =\dfrac{3}{5}\times\dfrac{6}{5}\times\dfrac{7}{6}\times\dfrac{8}{7}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{18}{25}\times\dfrac{4}{3}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{353}{175}\)
9,3 x 6,7 + 9,3 x 3,3 = 9,3 x ( 6,7 + 3,3 )
= 9,3 x 10
= 93
7,8 x 0,35 + 0,35 x 2,2 = 0,35 x ( 7,8 + 2,2 )
= 0,35 x 10
= 3,5
Đáp án là:
a) 9,3 x 6,7 + 9,3 x 3,3
= 9,3 x (6,7+3,3)
= 9,3 x 10
= 93.
b) 7,8 x 0,35 + 0,35 x 2,2
= 0,35 x (7,8+2,2)
= 0,35 x 10
= 35
\(\dfrac{16\times25+44\times100}{29\times96+124\times48}\)
\(=\dfrac{16\times25+44\times25\times4}{29\times2\times48+124\times48}\)
\(=\dfrac{25\times16+176\times25}{48\times\left(58+124\right)}\)
\(=\dfrac{25\times192}{48\times182}\)
\(=\dfrac{50}{91}\)
35 x 3/4 + 45,5 x 75/100 + 20,5 x 75% - 0,75
= 35 x 0,75 + 45,5 x 0,75 + 20,5 x 0,75 - 0,75 x 1
= ( 35 + 45,5 + 20,5 - 1 ) x 0,75
= 100 x 0,75
= 75
2 x 93 x 50 + 4 x 6 x 25 + 100
= (2 x 50) x 93 + (25 x 4) x 6 + 100
= 100 x 93 + 100 x 6 + 100 x 1
= 100 x (93 + 6 + 1)
= 100 x 100
= 10000
\(2.93.50+4.6.25+100\)
\(=\left(2.50\right).93+\left(4.25\right).6+100\)
\(=100.93+100.6+100\)
\(=100.\left(93+6+1\right)\)
\(=100.100\)
\(=10000\)