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\(\frac{2}{3}\times\frac{4}{5}+\frac{4}{5}\times\frac{1}{2}+\frac{4}{5}\times\frac{1}{6}\)
\(=\left(\frac{2}{3}+\frac{1}{2}+\frac{1}{6}\right)\times\frac{4}{5}\)
\(=\frac{4}{3}\times\frac{4}{5}\)
\(=\frac{16}{15}\)
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9+3+2+1+7+8+5+10+6+4= (9+1)+(2+8)+(3+7)+(4+6)+5=10+10+10+10+5=10.4+5=40+5=45
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a,Ta có \(\frac{x}{6}=\frac{2}{3}\)
\(\Rightarrow3x=12\Rightarrow x=4\)
Vậy x = 4
b, \(\left(\frac{4}{7}+\frac{8}{9}\right)-\frac{5}{9}=\frac{4}{7}+\frac{8}{9}-\frac{5}{9}\)
\(=\frac{4}{7}+\left(\frac{8}{9}-\frac{5}{9}\right)\)
\(=\frac{4}{7}+\frac{1}{3}\)
\(=\frac{19}{21}\)
Bài 1 mình nhầm. x phần 6 = 4 phần 7 mới đúng. Cảm ơn bạn nhé
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`7/9+9/7+6/9+11/7`
`=(7/9+6/9)+(9/7+11/7)`
`=13/9+20/7`
rồi thuận tiện nào cái bài này=)
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1) \(=\left(\frac{3}{5}+\frac{2}{5}\right).\frac{6}{11}\)
\(=1.\frac{6}{11}\)
\(=\frac{6}{11}\)
2)\(\frac{17}{25}.\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\)
\(=\frac{17}{25}.1\)
\(=\frac{17}{25}\)
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\(\dfrac{3}{5}+\dfrac{4}{7}+\dfrac{2}{5}+\dfrac{1}{7}+\dfrac{2}{7}\\ =\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{4}{7}+\dfrac{1}{7}+\dfrac{2}{7}\right)\\ =\dfrac{5}{5}+\dfrac{7}{7}\\ =1+1\\ =2\)
3/5 + 4/7 + 2/5 + 1/7 + 2/7
=(3/5 + 2/5) + (4/7 + 1/7 + 2/7)
= 1 + 1 = 2
3/5 và 2/5 có mẫu chung là 5, 2+3 = 5 => 5/5 = 1
4/7, 1/7 và 2/7 có mẫu chung là 7, 4+1+2 = 7 => 7/7 = 1
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1) 1/5 . 5/4 + 1/5 . 5/4
= (1/5 + 1/5) . 5/4
= 1/5 . 5/4
= 1/4
2)tự làm
1.\(\frac{1}{5}\times\frac{5}{4}+\frac{1}{5}\times\frac{5}{4}\)
\(=\frac{1}{5}\times\frac{5}{4}\times2\)
\(=\frac{1\times5\times2}{5\times4}\)
\(=\frac{1}{2}\)
2.\(\frac{7}{6}\times\frac{2}{5}-\frac{1}{3}\times\frac{2}{5}+\frac{5}{6}\times\frac{2}{5}\)
\(=\frac{2}{5}\times\left(\frac{7}{6}-\frac{1}{3}+\frac{5}{6}\right)\)
\(=\frac{2}{5}\times\left(\frac{7}{6}-\frac{2}{6}+\frac{5}{6}\right)\)
\(=\frac{2}{5}\times\frac{5}{3}\)
\(=\frac{2}{3}\)
\(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\Leftrightarrow\frac{4}{5}+\frac{1}{5}+\frac{2}{3}+\frac{1}{3}\)
\(\Rightarrow\left(\frac{4}{5}+\frac{1}{5}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)=1+1=2\)
\(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\)\(\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)\)
\(=1-1\)
\(=0\)