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a,2x-3=x+1/2 b,4x-(x+1/2)=2x+(1/2-5) c,2/3-1/3(x-2/3)-1/2(2x+1)=5
2x-x =1/2+3 4x-x-1/2=2x+1/2-5 d,(x+1/2).(x-3/4)=0
x=7/2 4x-x-2x =1/2-5+1/2 \(\orbr{\begin{cases}x+\frac{1}{2}=0\\x-\frac{3}{4}=0\end{cases}}\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{3}{4}\end{cases}}\)
x=-4
e,(2x-1)(3x+1/5)=0
\(\orbr{\begin{cases}2x-1=0\\3x+\frac{1}{5}=0\end{cases}}\orbr{\begin{cases}2x=1\\3x=\frac{1}{5}\end{cases}}\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{1}{15}\end{cases}}\)
f, 4x2-2x=0
Các câu mk chưa làm thì bạn cứ chờ để mk suy nghĩ.
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\(a,\Leftrightarrow-\dfrac{1}{2}x=\dfrac{1}{4}\Leftrightarrow x=-\dfrac{1}{2}\\ b,\Leftrightarrow\dfrac{1}{6}:x=\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{5}{6}\Leftrightarrow x=\dfrac{1}{6}:\dfrac{5}{6}=\dfrac{1}{5}\\ c,\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=3\\x+\dfrac{1}{5}=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{14}{5}\\x=-\dfrac{16}{5}\end{matrix}\right.\)
\(d,\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2=\dfrac{22}{9}-\dfrac{7}{3}=\dfrac{1}{9}\\ \Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{1}{3}\\x+\dfrac{1}{2}=-\dfrac{1}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{6}\\x=-\dfrac{5}{6}\end{matrix}\right.\\ e,\Leftrightarrow2\left|x\right|=2-\dfrac{1}{2}=\dfrac{3}{2}\\ \Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{3}{2}\\2x=-\dfrac{3}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=-\dfrac{3}{4}\end{matrix}\right.\)
\(f,\Leftrightarrow\left|x+\dfrac{1}{2}\right|=1+\dfrac{1}{6}=\dfrac{7}{6}\\ \Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{7}{6}\\x+\dfrac{1}{2}=-\dfrac{7}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{5}{3}\end{matrix}\right.\)
e: ta có: \(2\left|x\right|+\dfrac{1}{2}=2\)
\(\Leftrightarrow2\left|x\right|=\dfrac{3}{2}\)
\(\Leftrightarrow\left|x\right|=\dfrac{3}{4}\)
hay \(x\in\left\{\dfrac{3}{4};-\dfrac{3}{4}\right\}\)
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a) 1/7 - 3/5x = 3/5
3/5x= 1/7 - 3/5
3/5x = -16/35
x= -16/35 : 3/5 = -16/21
b) 3/7 - 1/2x = 5/3
1/2x = 3/7 - 5/3 = -26/21
x= -26/21 : 1/2 = -52/21
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\(a,\left|\frac{4x}{5}-\frac{2}{7}\right|-\frac{3}{2}=-\frac{2}{5}\)
\(\Leftrightarrow\left|\frac{4x}{5}-\frac{2}{7}\right|=\frac{11}{10}\)
Xét cả hai trường hợp :
Trường hợp 1 : \(\frac{4x}{5}-\frac{2}{7}=\frac{11}{10}\)
\(\Leftrightarrow\frac{4x}{5}=\frac{97}{70}\)
\(\Leftrightarrow4x=\frac{97}{14}\)
\(\Leftrightarrow x=\frac{97}{56}\)
Trường hợp 2 : \(\frac{4x}{5}-\frac{2}{7}=-\frac{11}{10}\)
\(\Leftrightarrow\frac{4x}{5}=-\frac{57}{50}\)
\(\Leftrightarrow4x=-\frac{57}{14}\)
\(\Leftrightarrow x=-\frac{57}{56}\)
\(b,\left|4x-\frac{1}{5}\right|=\left|2x+\frac{1}{2}\right|\)
\(\Leftrightarrow\orbr{\begin{cases}4x-\frac{1}{5}=2x+\frac{1}{2}\\4x-\frac{1}{5}=-2x+\frac{1}{2}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}4x-\frac{1}{5}-2x=\frac{1}{2}\\4x-\frac{1}{5}-(-2x)=-\frac{1}{2}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}4x-2x-\frac{1}{5}=\frac{1}{2}\\4x-(-2x)-\frac{1}{5}=-\frac{1}{2}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=\frac{7}{10}\\6x=-\frac{3}{10}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{20}\\x=-\frac{1}{20}\end{cases}}\)