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218-(x+31)=x-29
218-31=x+x-29
2x=218-31+29=218-(31-29)
2x=218-2=216
x=216/2
x=108
![](https://rs.olm.vn/images/avt/0.png?1311)
29 x (23 +15) - 23x( 29 +15)
= 29 x 23 + 29 x 15 - 23 x 29 - 23 x 15
= ( 29 x 23 - 23 x 29) + 15 x ( 29 - 23)
= 0 + 15 x 6
=90
![](https://rs.olm.vn/images/avt/0.png?1311)
\(218-\left(x+31\right)=x-29\)
\(\Leftrightarrow\)\(218-x-31=x-29\)
\(\Leftrightarrow\)\(187-x=x-29\)
\(\Leftrightarrow\)\(2x=216\)
\(\Leftrightarrow\)\(x=108\)
Vậy....
218-(x + 31) = x - 29
=> 218 - x - 31 = x - 29
=> (218-31) - x = x - 29
=> 187 - x = x - 29
=> -x - x = -29 - 187
=> -2x = -216
=> x = -216 : (-2)
=> x = 108
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 218 - ( x + 81 ) = x - 29
\( \implies\) 218 - x - 81 = x - 29
\( \implies\) 137 - x = x - 29
\( \implies\) 2x = 166
\( \implies\) x = 83
218 - (x +31)=x - 29
218 - x -31=x-29
218-x=x-29+31
218-x=x+2
x+2=218-x
2=218-x-x
2=218-Xx2
xX2=218-2
Xx2=216
x=216:2
x=108
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1 :
Ta có :
\(-\frac{7}{72}>-\frac{9}{72}\)
\(-\frac{9}{72}>-\frac{9}{40}\)
\(\Rightarrow-\frac{7}{72}>-\frac{9}{40}\)
Vậy \(-\frac{7}{72}>\frac{9}{-40}\)
Bài 2 :
218 - ( x + 3 ) = x - 29
218 - x - 3 = x - 29
218 - 3 + 29 = x + x
2x = 244
x = 122
Vậy x = 122
![](https://rs.olm.vn/images/avt/0.png?1311)
a) <=> -218 - x - 31 = x - 29
<=> 2x = -220
<=> x = -110
b) <=> -12x + 60 + 21 - 7x = 5
<=> -19x = -76
<=> x = 4
c) <=> 3x + 21 + 28 = 9 - 2x - 10
<=> 5x = -50
<=> x = -10
d) <=> 2x + 6 - 3x + 15 = 12 - 4x - 18
<=> 3x = -27
<=> x = -9
![](https://rs.olm.vn/images/avt/0.png?1311)