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4x(x-5)-(x-1)(4x-3) = 5
4x2 - 20x - [4x2 - 3x - (4x - 3)] = 5
4x2 - 20x - [4x2 - 3x - 4x + 3] = 5
4x2 - 20x - 4x2 + 3x + 4x - 3 = 5
-13x = 5 + 3
-13x = 8
x = \(\dfrac{\left(-8\right)}{13}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
4x ( x - 5 ) - ( x - 1 ) ( 4x - 3 ) = 5
<=> 4x2 - 20x - ( 4x2 - 7x + 3 ) = 5
<=> 4x2 - 20x - 4x2 + 7x - 3 = 5
<=> - 13x = 8
<=> x = - 8/13
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\Leftrightarrow x^2+6x+9-x^2+3x+10=1\\ \Leftrightarrow9x=-18\Leftrightarrow x=-2\\ b,\Leftrightarrow4x^2-4x+1-4x^2+17x+15=3\\ \Leftrightarrow13x=-13\Leftrightarrow x=-1\\ c,\Leftrightarrow3x\left(x-2\right)+4\left(x-2\right)=0\\ \Leftrightarrow\left(3x+4\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{4}{3}\\x=2\end{matrix}\right.\\ d,\Leftrightarrow2x\left(3x+5\right)-6\left(3x+5\right)=0\\ \Leftrightarrow\left(x-3\right)\left(3x+5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{5}{3}\end{matrix}\right.\)
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a) 4x2 - 2x + 3 - 4x.(x - 5) = 7x - 3
--> 4x2 - 2x + 3 - 4x2 + 20x = 7x - 3
--> 4x2 - 2x - 4x2 + 20x - 7x = -3 - 3
--> 11x = -6
--> x = \(\frac{-6}{11}\)
b) -3x.(x - 5) + 5.(x - 1) + 3x2 = 4x
--> -3x2 + 15x + 5x - 5 + 3x2 = 4x
--> -3x2 + 15x + 5x + 3x2 - 4x = 5
--> 16x = 5
--> x = \(\frac{5}{16}\)
c) 7x.(x - 2) - 5.(x - 1) = 21x2 - 14x2 + 3
--> 7x2 - 14x - 5x + 5 = 7x2 + 3
--> 7x2 - 14x - 5x - 7x2 = -5 + 3
--> -19x = -2
--> x = \(\frac{2}{19}\)
d) 3.(5x - 1) - x.(x - 2) + x2 - 13x = 7
--> 15x - 3 - x2 + 2x + x2 - 13x = 7
--> 15x - x2 + 2x + x2 - 13x = 3 + 7
--> 4x = 10
--> x = \(\frac{5}{2}\)
e) \(\frac{1}{5}\)x.(10x - 15) - 2x.(x - 5) = 12
--> 2x2 - 3x - 2x2 + 10x = 12
--> 7x = 12
--> x = \(\frac{12}{7}\)
~ Học tốt ~
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 4x2 - 2x + 3 - 4x(x - 5) = 7x - 3
=> 4x2 - 2x + 3 - 4x2 + 20x = 7x - 3
=> 18x + 3 = 7x - 3
=> 18x - 7x = -3 - 3
=> 11x = -6
=> x = -6/11
b) -3x(x - 5) + 5(x - 1) + 3x2 = 4x
=> -3x2 + 15x + 5x - 5 + 3x2 = 4x
=> 20x - 5 = 4x
=> 20x - 4x = 5
=> 16x = 5
=> x = 5/16
\(c,7x\left(x-2\right)-5\left(x-1\right)=21x^2-14x^2+3\)
\(\Leftrightarrow7x^2-14x-5x+5=7x^2+3\)
\(\Leftrightarrow7x^2-7x^2-19x=3-5\)
\(\Leftrightarrow-19x=-2\)
\(\Leftrightarrow x=\frac{2}{19}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(4x\left(x-5\right)-\left(x-1\right)\left(4x-3\right)=5\)
\(\Rightarrow4x^2-20x-4x^2+3x+4x-3=5\)
\(\Rightarrow-17x=8\)
\(\Rightarrow x=-\frac{8}{17}\)
4x(x - 5) - (x - 1)(4x - 3) = 5
<=> 4x2 - 20x - 4x2 + 7x - 3 = 5
<=> -13x = 5 + 3
<=> -13x = 8
<=> x = 8 : -13
<=> x = -8/13
![](https://rs.olm.vn/images/avt/0.png?1311)
1: Ta có: \(\left(x+3\right)^2-\left(x+2\right)\left(x-2\right)=4x+17\)
\(\Leftrightarrow x^2+6x+9-x^2+4-4x=17\)
\(\Leftrightarrow x=2\)
3: Ta có: \(\left(2x+3\right)\left(x-1\right)+\left(2x-3\right)\left(1-x\right)=0\)
\(\Leftrightarrow2x^2-2x+3x-3+2x-2x^2-3+3x=0\)
\(\Leftrightarrow6x=6\)
hay x=1
\(4x\left(x-5\right)-\left(x-1\right)\left(4x-3\right)=5\)
\(\Rightarrow4x^2-20x-4x^2+7x-3=5\)
\(\Rightarrow-13x=8\)
\(\Rightarrow x=-\frac{8}{13}\)
nhân bung ra ta có
\(4x^2-20x-4x^2+7x-3\)=5
<=> \(-13x-3=5\)
=> x = \(\frac{-8}{13}\)