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\(1\frac{1}{5}+\frac{4}{5}:x=0,75\)
\(\frac{6}{5}+\frac{4}{5}:x=\frac{3}{4}\)
\(\frac{4}{5}x=-\frac{9}{20}\)
\(x=-\frac{9}{16}\)
lỡ tay ấn đăng :((
\(\frac{1}{10}:\left(\frac{3}{4}-2x\right)^2=0,4\)
\(\left(\frac{3}{4}-2x\right)^2=\frac{1}{4}\)
\(\left(\frac{3}{4}-2x\right)^2=\left(\frac{1}{2}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}\frac{3}{4}-2x=\frac{1}{2}\\\frac{3}{4}-2x=-\frac{1}{2}\end{cases}\Rightarrow\orbr{\begin{cases}2x=\frac{1}{4}\\2x=\frac{5}{4}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{5}{8}\end{cases}}}\)
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1/
a, \(A=\dfrac{2}{3}+\dfrac{3}{4}.\left(-\dfrac{4}{9}\right)=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
b, \(B=2\dfrac{3}{11}.\dfrac{11}{12}.\left(-2,2\right)=\dfrac{25}{11}.\dfrac{11}{12}.\left(-\dfrac{11}{5}\right)=-\dfrac{55}{12}\)
c, \(C=\left(\dfrac{3}{4}-0,2\right):\left(0,4-\dfrac{4}{5}\right)=\left(\dfrac{3}{4}-\dfrac{1}{5}\right):\left(\dfrac{2}{5}-\dfrac{4}{5}\right)=\dfrac{11}{20}:\left(-\dfrac{2}{5}\right)=-\dfrac{11}{8}\)
2/
a, \(\dfrac{11}{12}-x=\dfrac{2}{3}+\dfrac{1}{4}\\ \Rightarrow\dfrac{11}{12}-x=\dfrac{11}{12}\\ \Rightarrow x=0\)
b, \(2x\left(x-\dfrac{1}{7}\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
c, \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\\ \Rightarrow\dfrac{1}{4}:x=-\dfrac{7}{20}\\ \Rightarrow x=-\dfrac{5}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
|2x-0,4| = 3,2
=> 2x -0,4 = 3,2 hoặc -3,2
=> 2x= 3,6 hoặc -2,8
=> x= 1,8 hoặc -1,4
Vậy \(x\in\left\{1,8;-1,4\right\}\)
2.
||x+3|-5| = 10
=> |x+3| -5 = 10 hoặc -10
=> |x+3| = 15 hoặc -5
mà |x+3| \(\ge\) 0
=> |x+3| = 15
=> x+3 = -15 hoặc 15
=> x= -18 hoặc 12
Vậy \(x\in\left\{-18;12\right\}\)
Trả lời
110.(34−2x)2=0,4110.(34-2x)2=0,4
⇔(34−2x)2=4⇔(34-2x)2=4
⇔(34−2x)2=22⇔(34-2x)2=22
⇔⇔ ⎡⎢ ⎢⎣34−2x=234−2x=−2[34−2x=234−2x=−2
⇔⇔ ⎡⎢ ⎢⎣x=−58x=118[x=−58x=118
Vậy S={−58;118}