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\(\frac{1}{3}.x+\frac{3}{4}.x-75\%=-\frac{21}{4}\)
\(\frac{1}{3}.x+\frac{3}{4}.x-\frac{3}{4}=-\frac{21}{4}\)
\(x.\left(\frac{1}{3}+\frac{3}{4}\right)=-\frac{21}{4}+\frac{3}{4}\)
\(x.\frac{13}{12}=-\frac{9}{2}\)
\(x=-\frac{9}{2}:\frac{13}{12}\)
\(x=-\frac{54}{13}\)
=> x.(1/3+3/4) -75/100=-21/4
=> x .13/12 - 3/4 =21/4
=> x. 13/12 =21/4 + 3/4
=> x.13/12 =6
=> x = 6 : 13/12
=> x = 72/13
vậy x= 72/13
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\(\frac{x}{3}=\frac{3}{x}\)
\(\Leftrightarrow9=x^2\)
\(\Leftrightarrow x=\sqrt{9}\)
\(\Leftrightarrow x\in\left\{-3;3\right\}\)
\(\frac{8}{5}=\frac{-12}{x}\)
\(\Leftrightarrow8x=-60\)
\(\Leftrightarrow x=\frac{-15}{2}\)
\(\frac{x}{-4}=\frac{-4}{x}\)
\(\Leftrightarrow-x^2=-16\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x=\sqrt{16}\)
\(\Leftrightarrow x\in\left\{-4;4\right\}\)
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20 . 2^x + 1 = 10.4^2 + 1
20 . 2^x + 1 = 10 . 16 + 1
20 . 2^x + 1 = 161
20 . 2^x = 161 - 1
20 . 2^x = 160
2^x = 8
2^x = 2^3
=> x = 3
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Ta có: \(\frac{x-4}{y-3}=\frac{4}{3}\)
=> 3 . (x-4) = 4 . (y-3)
= 3x - 12 = 4y - 12
=> 3x = 4y
=> \(\frac{3}{y}=\frac{4}{x}\)và x - y = 5
Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:
\(\frac{3}{y}=\frac{4}{x}=\frac{4-3}{x-y}=\frac{1}{5}=0,2\)
=> x = 0,2 x 4 = 0,8
y = 0,2 x 3 = 0,6
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\(a,\dfrac{3}{8}=\dfrac{6}{x}\\ \Rightarrow x=6:\dfrac{3}{8}\\ \Rightarrow x=16\\ b,\dfrac{1}{9}=\dfrac{x}{27}\\ \Rightarrow x=\dfrac{1}{9}.27\\ \Rightarrow x=3\\ c,\dfrac{4}{x}=\dfrac{8}{6}\\ \Rightarrow x=4:\dfrac{4}{3}\\ \Rightarrow x=3\\ d,\dfrac{3}{x-5}=\dfrac{-4}{x+2}\\ \Rightarrow3\left(x+2\right)=-4\left(x-5\right)\\ \Rightarrow3x+6=-4x+20\\ \Rightarrow3x+6+4x-20=0\\ \Rightarrow7x-14=0\\ \Rightarrow7x=14\\ \Rightarrow x=2\)
a: =>6/x=3/8
hay x=16
b: =>x/27=1/9
nên x=3
c: =>4/x=4/3
nên x=3
d: =>3/x-5=-4/x+2
=>3x+2=-4x+20
=>7x=18
hay x=18/7
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\(\Leftrightarrow x^2+7x+12⋮3x\)
=>3x^2+21x+36 chia hết cho 3x
=>36 chia hết cho 3x
=>\(3x\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;9;-9;12;-12;18;-18;36;-36\right\}\)
hay \(x\in\left\{\dfrac{1}{3};-\dfrac{1}{3};\dfrac{2}{3};-\dfrac{2}{3};1;-1;\dfrac{4}{3};-\dfrac{4}{3};2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
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4x + (1/99+2/98+3/97 + 4/96)=-4
4x=-4 - (1/99+2/98+3/97 + 4/96)
4x=
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Dấu / / là j đấy bạn
chắc là giá trị bn ạ