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a) 416 + ( x-45 )= 387
416-45+x=387
x=387-(416-45)
x=16
b) 11-(x+84)=97
11-x-84=97
-x=84-11+97
-x=170
x=-170
c) -(x+84)+213=-16
-x-84+213=-16
-x=-16-213+84
-x=-145
x=145
d)x+(-35)=18
x-35=18
x=53
e) -2x-(-17)=15
-2x+17=15
-2x=-2
x=1
P/s tham khảo nha
A) 416 + (X-45) =387
416+X-45= 387
416-45+X=387
371+X=387
X=387-371
X=16
B) 11-(X+84)=97
11-X-84=97
11-84-X=97
-73-X=97
X=-73-97
X=-170
C) -(X+84) +213=-16
-X-(84-213) =-16
-X-(-129)=-16
-X=(-16)+(-129)
-X= -145
X=145
D) X+(-35)=18
X=18-(-35)
X=53
E) -2X-(-17) =15
-2X+17=15
-2X=15-17
-2X=-2
X=-2:-2
X=1
![](https://rs.olm.vn/images/avt/0.png?1311)
a, - ( x + 84 ) + 213 = -16
=> - ( x + 84 ) = -16 - 213
=> - ( x + 84 ) =-229
=> x + 84 = 229
=> x = 145
b. x + ( -35 ) = 18
=> x = 18 - ( -35 )
=> x = 18 + 35
=> x = 53
c. -2x - ( - 17 ) = 15
=> -2x = 15 + ( -17)
=> -2x = -2
=> x = 1
\(a,-\left(x+84\right)+213=-16\)
\(x+84=213+16\)
\(x+84=229\)
\(x=229-84\)
\(x=145\)
\(b,x+\left(-35\right)=18\)
\(x=18+35\)
\(x=53\)
\(c,-2x-\left(-17\right)=15\)
\(-2x+17=15\)
\(2x=17-15\)
\(2x=2\)
\(x=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Giải:
Bài 1:
a) \(6^2\): 4 . 3 + 2 . \(5^2\)
= 36 : 4 . 3 + 2 . 25
= 27 + 50
= 77
77 = 7 . 11
b) 5 . \(4^2\) - 18 : \(3^2\)
= 5 . 16 - 18 : 9
= 80 - 2
= 78
78 = 2 .3 . 13
Bài 2:
a) Ta có: \(70⋮x\)
\(84⋮x\)
Do đó: \(x\inƯC\left(70;84\right)\)
\(\Leftrightarrow x\inƯ\left(14\right)\)
\(\Leftrightarrow x\in\left\{1;2;7;14\right\}\)
mà x>8
nên x=14
![](https://rs.olm.vn/images/avt/0.png?1311)
a, -14 - 7 + x = -12
\(\Leftrightarrow-21+x=-12\)
\(\Leftrightarrow x=-12+21\)
\(\Leftrightarrow x=9\)
b, \(x+\left(-15\right)-\left(-6\right)=11\)
\(\Leftrightarrow x-15+6=11\)
\(\Leftrightarrow x-\left(15-6\right)=11\)
\(\Leftrightarrow x-9=11\)
\(\Leftrightarrow x=11+9\)
\(\Leftrightarrow x=20\)
c, \(x-\left[18+\left(-7\right)\right]=15\)
\(\Leftrightarrow x-\left(18-7\right)=15\)
\(\Leftrightarrow x-11=15\)
\(\Leftrightarrow x=15+11\)
\(\Leftrightarrow x=26\)
d, \(-84-\left(-18-6\right)=x+\left(-20\right)\)
\(\Leftrightarrow-84-\left(-24\right)=x+\left(-20\right)\)
\(\Leftrightarrow-84+24=x+\left(-20\right)\)
\(\Leftrightarrow-60=x+\left(-20\right)\)
\(\Leftrightarrow x=-20+60\)
\(\Leftrightarrow x=40\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a -20<x<21
x\(\varepsilon\){ -19;-18;-17;-16;-15;-14;-13;-12;.......;20}
Tổng các số hạng
(-19)+(-18)+(-17)+.......+19+20
= [(-19)+9] + [ (-18)+18 ]+....+[(-1)+1)+0 +20
=0+0+...+0+20=20
b -18<x<17
x\(\varepsilon\){ -17;-16;.......;15;16}
tổng các số hạng
(-17)+(-16)+(-15)+...+15+16
= (-17)+[(-16)+16]+[(-15)+15]+...+0
=(-17) +0+0+...+0
=-17
c tương tự
d |x|\(\le\)3
|x|\(\le\)3 suy ra x \(\varepsilon\){ 0;1;2;3}
nếu |x| =0 suy ra x =0
nếu |x|=1suy ra x=\(\pm\)1
nếu |x|=2 suy ra x=\(\pm\)2
nếu |x| =3 suy ra x=\(\pm\)3
vậy x thuộc -3;-2;-1;0;1;2;3
câu e tương tự
![](https://rs.olm.vn/images/avt/0.png?1311)
-18<x<17
\(\Rightarrow x\in\left\{-18;-17;-16;...;17\right\}\)
-27<x<27
\(\Rightarrow x\in\left\{-27;-26;-25;...;27\right\}\)
|x|<3
\(\Rightarrow x\in\left\{\pm1;\pm5\right\}\)
|-x|<5
\(\Rightarrow x\in\left\{\pm1\right\}\)
chúc bạn học tốt !!!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a)\frac{-84}{14}< 3x< \frac{108}{9}\)
\(\Rightarrow-6< 3x< 12\)
\(\Rightarrow-2< x< 4\)
\(\Rightarrow x=3\)
\(c)\frac{x-1}{9}=\frac{8}{3}\)
\(\Rightarrow x-1=\frac{8}{3}\cdot9\)
\(\Rightarrow x-1=24\)
\(\Rightarrow x=25\)
\(d)\frac{-x}{4}=\frac{-9}{x}\)
\(\Rightarrow(-x)\cdot x=(-9)\cdot4\)
\(\Rightarrow-x^2=-36\)
\(\Rightarrow x=\pm6\)
\(e)\frac{x}{4}=\frac{18}{x+1}\)
\(\Rightarrow x(x+1)=18\cdot4\)
\(\Rightarrow x(x+1)=72\)
\(\Rightarrow x(x+1)=8\cdot9=(-9)\cdot(-8)\)
Do đó : x = 8 hoặc x = -9
<=> 3 . ! x ! + 18 = -27 + 84
<=> 3 . ! x ! + 18 = 57
<=> 3 . ! x ! = 57 - 18
<=> 3 . ! x ! = 39
<=> ! x ! = 39 : 3
<=> ! x ! = 13
<=> x = 13 hay x = -13
3 x |x|-(-18)=75
3 x |x|=75-18
3x|x|=57
|x|=57:3
|x|=19
=>x=19hoặcx=-19