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\(\Leftrightarrow\)\(5x+10-25=0\)
\(\Leftrightarrow\)\(5x=15\)
\(\Leftrightarrow\)\(x=\frac{15}{5}=3\)
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2X.(32+16.13:16-15)-5.2^3=0
(=)2X.(32+13-15)-5.8=0
(=) 2X.30-40=0
(=) 2X.30=40
(=) 2X=10
(=) X=5
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a)\(\left(x-140\right)\)\(\div\)7=27-4-3 =20\(\Rightarrow\) \(\left(x-140\right)\) =20x7=140\(\Rightarrow\) x=0
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Tìm x εIN biết
a) 390 - (x-8) = 168:13
b) (x-140) : 7 = 27 - 24
c) x- 6 :2 - ( 48 - 24 ) :2 :6 - 3 = 0
d) x+5.2-(32+16.3:6-15)=0
b) \(\left(x-140\right):7=27-24\)
\(\left(x-140\right):7=3\)
\(x-140=21\)
\(x=161\)
vay \(x=161\)
c) \(x-6:2-\left(48-24\right):2:6-3=0\)
\(x-3-24:2:6-3=0\)
\(x-3-2-3=0\)
\(x-8=0\)
\(x=8\)
vay \(x=8\)
d) \(x+5.2-\left(32+16.3:6-15\right)=0\)
\(x+10-\left(32+8-15\right)=0\)
\(x+10-25=0\)
\(x-15=0\)
\(x=15\)
vay \(x=15\)
a) \(390-\left(x-8\right)=168:13\)
\(390-x+8=\frac{168}{13}\)
\(x+8=390-\frac{168}{13}\)
\(x+8=\frac{5070}{13}-\frac{168}{13}\)
\(x+8=\frac{4902}{13}\)
\(x=\frac{4902}{13}-8\)
\(x=\frac{4798}{13}\)
vay \(x=\frac{4798}{13}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 460 + 85 * 4 = ( x + 200 ) * 4
460 + 340 = ( x + 200 ) * 4
800 = ( x + 200 ) * 4
x + 200 = 200
x = 0
b) x + 5 * 2 - ( 32 + 16 * 3 : 16 - 15 ) = 0
x + 10 - ( 32 + 3 - 15 ) 0
x + 10 - 20 = 0
x - 10 = 0
x = 10
a) \(460+85.4=\left(x+200\right).4\)
\(\Rightarrow460+340=4x+800\)
\(\Rightarrow-4x=800-460-340\)
\(\Rightarrow-4x=0\)
\(\Rightarrow x=0\)
Vậy x = 0
b) \(x+5.2-\left(32+16.3:16-15\right)=0\)
\(\Rightarrow x+10-\left(32+3-15\right)=0\)
\(\Rightarrow x+10-20=0\)
\(\Rightarrow x-10=0\)
\(\Rightarrow x=10\)
Vậy x = 10
(2x+5):4-(32+16.3:6-15)=0
(2x+5):4-25=0
(2x+5):4 =0+25
(2x+5):4 =25
(2x+5) =25:4
2x+5 =6,25
2x =6,25-5
2x =1,25
x =1,25:2
x =0,625
các bạn nhớ k cho mình nha
(2x + 5 ): 4 - ( 32 + 16.3 : 6 - 15 ) = 0
(2x + 5 ) : 4 - ( 32 + 48 : 6 - 15 ) = 0
(2x + 5 ) : 4 - ( 32 + 8 - 15 ) = 0
(2x + 5) : 4 - 25 = 0
(2x + 5) : 4 = 0 + 25
(2x + 5 ) : 4 = 25
2x + 5 = 25 x 4
2x + 5 = 100
2x = 100 - 5
2x = 95
=> x = 95 : 2 = 47,5