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a: \(\left(x+\dfrac{1}{4}\right)+\left(3x-4\right)+2\left(x-3\right)=1\)
=>\(x+\dfrac{1}{4}+3x-4+2x-6=1\)
=>\(6x-\dfrac{39}{4}=1\)
=>\(6x=1+\dfrac{39}{4}=\dfrac{43}{4}\)
=>\(x=\dfrac{43}{4}:6=\dfrac{43}{24}\)
b: \(2\left(x-3\right)=3\left(x+2\right)-x+1\)
=>\(2x-6=3x+6-x+1\)
=>2x-6=2x+7
=>-6=7(vô lý)
c: \(x\left(x+3\right)+x\left(x-2\right)=2x\left(x-1\right)\)
=>\(x^2+3x+x^2-2x=2x^2-2x\)
=>3x-2x=-2x
=>3x=0
=>x=0
d: \(\left(x-1\right)\cdot3x-2\left(x+2\right)-2x=x\left(x-1\right)\)
=>\(3x^2-3x-2x-4-2x=x^2-x\)
=>\(3x^2-7x-4-x^2+x=0\)
=>\(2x^2-6x-4=0\)
=>\(x^2-3x-2=0\)
=>\(x=\dfrac{3\pm\sqrt{17}}{2}\)
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a/ 3(1 - x) - 5(2x - 2) = 0
=> 3 - 3x - 10x + 10 = 0
=> -13x = -13
=> x = 1
Vậy x = 1
b/ |3x - 2| - 4 = 0 => |3x - 2| = 4
Suy ra 2 trường hợp:
- 3x - 2 = 4 => 3x = 6 => x = 2
- 3x - 2 = -4 => 3x = -2 => x = -2/3
Vậy x = 2 , x = -2/3
c/ 2x - x3 = 0 => x.(2 - x2) = 0
=> x = 0
hoặc 2 - x2 = 0 => x2 = 2 => x = \(\sqrt{2}\) hoặc x = \(-\sqrt{2}\)
Vậy \(x=\left\{0;\sqrt{2};-\sqrt{2}\right\}\)
d/ x(1 - 2x) + (2x2 - x + 4) = 0
=> x - 2x2 + 2x2 - x + 4 = 0
=> 4 = 0 (vô lí)
Vậy vô nghiệm
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a,
*\(P\left(x\right)\) = \(-3x^2+4x-x^3+x^2+3x-1\)
\(P(x)=-3x^2+7x-x^3-1\)
\(P(x)=-x^3-3x^2+7x-1\)
* \(Q(x)=3x^4-x^2+x^3-2x-1-2x^3\)
\(Q(x)=3x^4-x^2-x^3-2x-1\)
\(Q(x)=3x^4-x^3-x^2-1\)
b, \(M(x)=P(x)-Q(x)\)
\(M(x)=-x^3-3x^2+7x-1-3x^4+x^3+x^2+1\)
\(M(x)=-2x^2+7x-3x^4\)