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![](https://rs.olm.vn/images/avt/0.png?1311)
8 = 23 ; 9 = 32 ; 11 = 11
=> BCNN(8;9;11) = 23 . 32 . 11 =792
![](https://rs.olm.vn/images/avt/0.png?1311)
10;12;15
10=2.5
12=2^2.3
15=3.5
bcnn(10;12;15)=2^2.3.5=60
8;9;11
bcnn(8;9;110)=8.9.11=792
vì 3 số là số nguyên tố cùng nhau
24;40;168
20=2^2.5
40=2^3.5
168=2^3.3.7
bcnn(24;40;168)=2^3.5.7=280
10=2.5
12=22.3
15=3.5
BCNN:4.3.5
8;9;11
vi 3 so deu la so nguyen to nen
BCNN:8.9,11=792
24;40;16
24=23.3
40=23.5
168=2.2.2.3.7
UCLN:23.3=24
TSR=5.7
BCNN:24.5.7=4200
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Ta có : 10=2.5
12=2^2 . 3
15=3.5
=> BCNN(10,12,15)=2^2.3.5=60
b, Ta có : 8 = 2^3
9 = 3^2
=>BCNN(8,9,11)=2^3 . 3^2 . 11 = 792
c, Ta có : 24=3. 2^3
40=2^3.5
168=2^3 .3.7
=>BCNN(24,40,168)=2^3 . 3.5.7=840
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
10.2=20;
=>BCNN(20,15)={0;60;120;180;240;..}
BCNN(8,9,11)={0;88;176;264}
![](https://rs.olm.vn/images/avt/0.png?1311)
1) Ta có: 10 = 2.5
12 = 22.3
15 = 3.5
=> BCNN(10;12;15) = 22.3.5 = 60
2) Do 8;9;11 nguyên tố cùng nhau từng đôi một => BCNN(8;9;11) = 8.9.11 = 792
3) Ta có: 24 = 23.3
40 = 23.5
168 = 23.3.7
=> BCNN(24;40;168) = 23.3.5.7 = 840
BCNN(10,12,15) là:
10=2.5
12=22.3
15=3.5
=>BCNN(10,12,15)=22.3.5=60
BCNN(8,9,11):
8=23
9=32
11=11
=>BCNN(8,9,11)=23.32.11=792
BCNN(24,40,168):
24=23.3
40=23.5
168=23.3.7
=> BCNN(24;40;168)=23.3.5.7=840
![](https://rs.olm.vn/images/avt/0.png?1311)
a)BCNN(10;12;15)=60
b)BCNN(8;9;11)=792
c)BCNN(24;40;168)=840
BCNN (8;9;11)=8.9.11=792