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\(a.10^{30}=\left(10^3\right)^{10}=1000^{10}\\ 2^{100}=\left(2^{10}\right)^{10}=1024^{10}\)
Vì 100010 < 102410 => 1030 < 2100
\(b,333^{444}=\left(111\cdot3\right)^{444}=111^{444}\cdot3^{444}=111^{444}\cdot81^{111}\\ 444^{333}=\left(111\cdot4\right)^{333}=111^{333}\cdot4^{333}=111^{333}\cdot64^{111}\)
Vì 111444 >111333 ; 81111 > 64111 => 333444 > 444333
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a) 1024 9 = ( 2 10 ) 9 = 2 90 < 2 100
b) 6 . 5 29 > 5 . 5 29 = 5 30
c) 10 30 = ( 10 3 ) 10 = 1000 10 ; 2 100 = ( 2 10 ) 10 = 1024 10 n ê n 10 30 < 2 100 .
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a: \(5^{300}=25^{150}\)
\(3^{450}=27^{150}\)
mà 25<27
nên \(5^{300}< 3^{450}\)
a: 5300=251505300=25150
3450=271503450=27150
mà 25<27
nên 5300<3450
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a: 5^30*25=5^30*5^2=5^32<5^34
b: 16^6=(2^4)^6=2^24<2^25
c: 10^30=1000^10
4^50=(4^5)^10=1024^10
=>10^30<4^50
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a ) 3 20 > 27 4 b ) 5 34 > 25 . 5 30 c ) 2 25 > 16 6 d ) 10 30 < 4 50
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a) Cách 1: 2 100 = 2 10 10 = 1024 10 > 1024 9
Cách 2: 1024 9 = 2 10 9 = 2 90 < 2 100
b) 6 . 5 29 > 5 . 5 29 = 5 30
c) 2 98 = 2 2 49 = 4 49 < 9 49
d) 10 30 = 10 3 10 = 1000 10 ; 2 100 = 2 10 10 = 1024 10 nên 10 30 < 2 100
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Ta có : \(A=1+2+2^2+...+2^{2017}\)(1)
\(\Rightarrow2A=2+2^2+2^3+...+2^{2018}\)(2)
Lấy (2) trừ (1) ta có :
\(\Rightarrow A=2^{2018}-1\)
\(\Rightarrow A< B\). Vì \(B=2^{2018}\)
A = 1+2+22+23+.....+22017
2A = 2(1+2+22+23+.....+22017) = 2+22+23+24+.....+22018
2A - A = 2+22+23+24+.....+22018- (1+2+22+23+.....+22017)
=> A = 2+22+23+24+.....+22018-1-2-22-23-.....-22017
A =22018-1 < 22018
Vậy A < B
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A = 123 × 123
A = (121 + 2) × 123
A = 121 × 123 + 2 × 123
B = 121 × 124
B = 121 × (123 + 1)
B = 121 × 123 + 121
Vì 2 x 123 > 121
=> A > B
theo đề bài ta có:
A=123 * 123
A=123*(121+2)
A=123*121 +123*2
B=121*124
B=121*(123+1)
B=123*121+121*1
B=121*123+121
vì 123*2>121=>a>b
\(10^{30}=10^{30}\)
\(1000^{20}=\left(10^3\right)^{20}=10^{60}\)
vi \(10^{60}>10^{30}\) nen \(10^{30}< 1000^{20}\)
TA CÓ: \(1000^{20}=\left(10^3\right)^{20}=10^{60}\)
DO \(10^{30}< 10^{60}\Rightarrow10^{30}< 1000^{20}\)