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a) Ta có:
\(\frac{23}{3}=\frac{21+2}{3}=\frac{21}{3}+\frac{2}{3}=7+\frac{2}{3}\)
\(\frac{15}{2}=\frac{14+1}{2}=\frac{14}{2}+\frac{1}{2}=7+\frac{1}{2}\)
Lại có:\(1-\frac{2}{3}=\frac{1}{3}< 1-\frac{1}{2}=\frac{1}{2}\Rightarrow\frac{2}{3}>\frac{1}{2}\)
\(\Rightarrow\frac{23}{3}>\frac{15}{2}\)
a, 23/3 và 15/2
Ta có :
23/3 = 23x2/3x2 = 46/6. 15/2 = 15x3/2x3 = 45/6.
Vậy 46/6 > 45/6 nên 23/3 > 15/2.
b, 4/17 và 2/9.
Ta có :
4/17 = 4x9/17x9 = 36/153. 2/9 = 2x17/9x17 = 34/153.
Vậy 36/153 > 34/153 nên 4/17 > 2/9.
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\(\frac{2}{7}=\frac{2.9}{7.9}=\frac{18}{63}\)
\(\frac{4}{9}=\frac{4.7}{9.7}=\frac{28}{63}\)
\(Vì\frac{18}{63}<\frac{28}{63}nên\frac{2}{7}<\frac{4}{9}\)
Các câu khác tương tự !!
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\(3=\frac{15}{5}\)
\(\frac{4}{10}=\frac{2}{5}\)
\(\frac{5}{9}=\frac{10}{18}\)
\(2=\frac{36}{18}\)
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9/10 ..... 9 + 3/10 + 3
9/10....... 12/13
9/10=117/130
12/13 = 120/130
Vì 120/130 > 117/130 Nên 9 + 3/10 + 3 > 9/10
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a) \(\dfrac{7}{9}=\dfrac{14}{18}=\dfrac{21}{27}=\dfrac{28}{36}\)
b) \(\dfrac{23}{37}=\dfrac{46}{74}=\dfrac{69}{111}=\dfrac{92}{148}\)
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\(\frac{5}{9}=\frac{10}{18}=\frac{15}{27}=\frac{20}{36}=\frac{25}{45}\)
\(\frac{15}{19}=\frac{30}{38}=\frac{45}{57}=\frac{60}{76}=\frac{75}{95}=\frac{90}{114}\)