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Ta có:a)\(^{3^{600}}\)=\(^{\left(3^3\right)^{200}}\)=\(^{27^{200}}\) \(^{4^{400}}\)=\(^{\left(4^2\right)^{200}}\)=\(^{16^{200}}\)
vì 27^200>16^200 => 3^600>4^400
b) \(^{4^{32}=4^{2.16}=16^{16}}\) vì 16^16>16^15 => 4^32>16^15
\(3^{600}=3^{200.3}=\left(3^3\right)^{200}=9^{200}^{_{\left(1\right)}}\)
\(4^{400}=\left(2^2\right)^{400}=2^{800}=2^{200.4}=\left(2^4\right)^{200}=16^{200}_{\left(2\right)}.\)
\(\left(1\right),\left(2\right)\Rightarrow4^{400}>3^{600}\)
\(4^{32}=\left(2^2\right)^{32}=2^{64}_{\left(1\right)}\)
\(16^{15}=\left(2^4\right)^{15}=2^{60}_{\left(2\right)}\)
\(\left(1\right),\left(2\right)\Rightarrow4^{32}>16^{15}\)
a/ \(3^{600}=\left(3^3\right)^{200}=\left(27\right)^{200}\)
\(4^{400}=\left(4^2\right)^{200}=\left(16\right)^{200}\)
\(\Leftrightarrow3^{600}>4^{400}\)
b/ \(4^{32}\)
\(16^{15}=\left(4^2\right)^{15}=4^{30}\)
\(\Leftrightarrow4^{32}>16^{15}\)
a)\(3^{600}\) = \(\left(3^3\right)^{200}\) = \(27^{200}\)
\(4^{400}\) = \(\left(4^2\right)^{200}\) = \(16^{200}\)
Vì \(27>16\Rightarrow27^{200}>16^{200}=3^{600}>4^{400}\)
Vậy\(3^{600}>4^{400}\)
b) \(32^{10}=\left(2^5\right)^{10}=2^{50}
\)
\(16^{15}=\left(2^4\right)^{15}=2^{60}\)
Vì \(50< 60\Rightarrow2^{50}< 2^{60}\Rightarrow32^{10}< 16^{15}\)
Vậy\(32^{10}< 16^{15}\)
a) Ta có
\(\sqrt{35}< \sqrt{36}=6\)
\(\sqrt{99}< \sqrt{100}=10\)
\(\Rightarrow\sqrt{35}+\sqrt{99}< 10+6=16\)
b) Ta có
\(\sqrt{50}>\sqrt{49}=7\)
\(\sqrt{17}>\sqrt{16}=4\)
\(\Rightarrow\sqrt{50}+\sqrt{17}>7+4=11\)
\(3^{600};4^{400}\)
\(3^{600}=\left(3^3\right)^{200}\)
\(4^{400}=\left(4^2\right)^{200}\)
Vì : \(27^{200}>16^{200}\)
\(\Rightarrow3^{600}>4^{400}\)
Ta có:
\(3^{600}=3^{3\times200}=\left(3^3\right)^{200}=27^{200}\)
\(4^{400}=4^{2\times200}=\left(4^2\right)^{200}=16^{200}\)
Vì 27 > 16 \(\Rightarrow27^{200}>16^{200}\Leftrightarrow3^{600}>4^{400}\)
ta có : \(3^{600}=\left(3^3\right)^{200}=9^{200}\)
\(5^{400}=\left(5^2\right)^{200}=25^{200}\)
vì \(9< 25\Rightarrow3^{600}< 5^{400}\)
Ta có:
+ 3600= 33.200 =(33)200=9200
+5400=52.200 =(52)200=25200
Do 9< 25 nên 9200 < 25200
Vậy 3600< 5400
Ta có : \(2^{600}=\left(2^3\right)^{200}=8^{200}\)
\(3^{400}=\left(3^2\right)^{200}=9^{200}\)
Vì \(8^{200}< 9^{200}\)
Nên \(2^{600}< 3^{400}\)
\(2^{600}=2^{3.200},3^{400}=3^{2.200}\)
Em so sánh 2^3 và 3^2