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Cho phép mình làm bài này theo cái đề do bạn Nguyễn Bảo Trung chữa lại nhé Nguyễn Lê Ngọc Thanh
\(A=\dfrac{11\cdot13\cdot15+33\cdot39\cdot45+55\cdot65\cdot75+99\cdot117\cdot135}{13\cdot15\cdot17+39\cdot45\cdot51+65\cdot75\cdot85+117\cdot135\cdot153}\text{ và }B=\dfrac{1111}{1717}\\ \)
\(\text{Ta có : }\)
\(A=\dfrac{11\cdot13\cdot15+33\cdot39\cdot45+55\cdot65\cdot75+99\cdot117\cdot135}{13\cdot15\cdot17+39\cdot45\cdot51+65\cdot75\cdot85+117\cdot135\cdot153}\\ A=\dfrac{11\cdot13\cdot15+3\cdot11\cdot13\cdot15+5\cdot11\cdot13\cdot15+9\cdot11\cdot13\cdot15}{13\cdot15\cdot17+3\cdot13\cdot15\cdot17+5\cdot13\cdot15\cdot17+9\cdot13\cdot15\cdot17}\\ A=\dfrac{11\cdot13\cdot15\left(1+3+5+9\right)}{13\cdot15\cdot17\left(1+3+5+9\right)}\\ A=\dfrac{11}{17}\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\left(1\right)\)
\(B=\dfrac{1111}{1717}\\ B=\dfrac{11\cdot101}{17\cdot101}\\ B=\dfrac{11}{17}\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\text{ }\left(2\right)\)
Từ \(\left(1\right)\) và \(\left(2\right)\) suy ra :
\(A=B=\dfrac{11}{17}\)
\(\Rightarrow A=B\)
Vậy \(A=B\)
Bn ơi , mik nghĩ mẫu số của A có cái 11.13.17 phải là 13.15.17
![](https://rs.olm.vn/images/avt/0.png?1311)
a)3200=(32)100=9100
2300=(23)100=8100
vì 9>8 nên 9100>8100
hay 3200>2300
b)\(A=\frac{121212}{171717}+\frac{2}{17}-\frac{404}{1717}=\frac{12.10101}{17.10101}+\frac{2}{17}-\frac{4.101}{17.101}=\frac{12}{17}+\frac{2}{17}-\frac{4}{17}\)
\(=\frac{10}{17}=B\)
Vậy A=B
a) Ta có: 3200 = ( 32 )100 = 9100
2300 = ( 23 )100 = 8100
Vì 9 > 8 nên 9100 > 8100.
Vậy 3200 > 2300
b) \(A=\frac{121212}{171717}+\frac{2}{17}-\frac{404}{1717}=\frac{12}{17}+\frac{2}{17}-\frac{4}{17}=\frac{12+2-4}{17}=\frac{10}{17}=B\)
Vậy A = B
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)