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![](https://rs.olm.vn/images/avt/0.png?1311)
a) (3 + 2i)[(2 – i) + (3 – 2i)]
= (3 + 2i)(5 – 3i) = 21 + i
b)(4−3i)+1+i2+i=(4−3i)+(1+i)(2−i)5=(4−3i)(35+15i)=(4+35)−(3−15)i=235−145i(4−3i)+1+i2+i=(4−3i)+(1+i)(2−i)5=(4−3i)(35+15i)=(4+35)−(3−15)i=235−145i
c) (1 + i)2 – (1 - i)2 = 2i – (-2i) = 4i
d) 3+i2+i−4−3i2−i=(3+i)(2−i)5−(4−3i)(2+i)5=7−i5−11−2i5=−45+15i
![](https://rs.olm.vn/images/avt/0.png?1311)
a) thực =1; ảo =4
b)thực= -7; ảo= 6\(\sqrt{2}\)
c)thực=13; ảo=0
d)thực=1; ảo=7
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow\left(i^2+4i+4\right)\left(1-i\right)z=4-3i+\left(3+i\right)z\)
\(\Leftrightarrow\left(4i+3\right)\left(1-i\right)z-\left(3+i\right)z=4-3i\) (do \(i^2=-1\Rightarrow i^2+4=3\))
\(\Leftrightarrow\left(4i-4i^2+3-3i\right)z-\left(3+i\right)z=4-3i\)
\(\Leftrightarrow\left(7+i\right)z-\left(3+i\right)z=4-3i\)
\(\Leftrightarrow4z=4-3i\)
\(\Leftrightarrow z=1-\dfrac{3}{4}i\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (3 + 4i)x = (1 + 2i)(4 + i)
b) 2ix + 3 = 5x + 4i
c) 3x(2 – i) + 1 =2ix(1 + i) + 3i
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ \(\left(2-3i\right)\left(2+3i\right)=4-9i^2=4+9=13\)
b/ \(\left(2+3i\right)\left(4-i\right)=8-2i+12i-3i^2=11+10i\)
c/ \(=\dfrac{\left(1+i\right)\left(2+3i\right)}{4-9i^2}=\dfrac{2+5i-3}{4+9}=\dfrac{5i-1}{13}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 2i(3 + i)(2 + 4i) = 2i(2 + 14i) = -28 + 4i
b)
c) 3 + 2i + (6 + i)(5 + i) = 3 + 2i + 29 + 11i = 32 + 13i
d) 4 - 3i + = 4 - 3i +
= 4 - 3i +
= (4 + ) - (3 +
)i =
Đáp án B