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![](https://rs.olm.vn/images/avt/0.png?1311)
A=3(2x-1) - I x-5 I (*)
a)xét 2 th:
TH(1) : A=6x-3-x+5 (x-5>=0) = 5x-2
TH(2) : A=6x-3-5+x (x-5<0) = 7x-8
b)có I x-3I=6 => x-3=6 (x-3>=0) hay x-3= -6 (x-3<0)
<=> x=9 (x-3>=0) hay x= -3 (x-3<0)
thay x=9 (x-3>=0) vào (*)
A = 47
thay x= -3 (x-3<0) vào (*) => A= -29
Chúc bạn học tốt!
![](https://rs.olm.vn/images/avt/0.png?1311)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: R=4x+5-4|x-5|
\(=4x+5-4\left(5-x\right)\)
\(=4x+5-20+4x\)
=8x-15
![](https://rs.olm.vn/images/avt/0.png?1311)
Do x < 2 => 2 - x âm => |2 - x| = -(2 - x) = -2 + x
Ta có:
B = 5 - (-2 + x)
B = 5 + 2 - x
B = 7 - x
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=5-\left|2-x\right|\)
\(=5\left(2-x\right)\) (vì x<2)
\(=10-5x\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
C=|5-x|-5|2-x|
=>C=|5-x|-2|5-x|
=>C=-|5-x|
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