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a, A:B = 2 29 . 3 18 : 2 28 . 3 18 = 2
b, C:D = 729.2910:729.2910 = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{32.9.11}{12.24.22}\) = \(\dfrac{8.4.3.3.11}{3.4.8.3.11.2}\) = \(\dfrac{1}{2}\)
\(\dfrac{32.9.11}{12.24.22}=\dfrac{8.4.3.3.11}{3.4.8.3.11.2}=\dfrac{1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{72\times75}{125\times108}\) = \(\dfrac{36\times2\times25\times3}{25\times5\times36\times3}\) = \(\dfrac{2}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bước rút gọn là sai vì không có tính chất
.
Sửa lại như sau:
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{3001500}{1010012}=\dfrac{3001500:116}{1010012:116}=\dfrac{25875}{8707}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A = 5 + 5 ^ 2 + 5 ^ 3 + ... + 5 ^ 50
5 A = 5 ^ 2 + 5 ^ 3 + 5 ^ 4 + ... + 5 ^ 51
5 A - A = ( 5 ^ 2 + 5 ^ 3 + 5 ^ 4 + ... + 5 ^ 51 )
- ( 5 + 5 ^ 2 + 5 ^ 3 + ... + 5 ^ 50 )
4 A = 5 ^ 51 - 5
A = \(\frac{5^{51}-5}{4}\)
A=5^1+5^21+5^3+...+5^50
5^1A=5(5^1+5^2+5^3+..+5^50)
5A=5^2+5^3+..+5^50+5^51
5A-A=(5^2+5^3+..+5^50+5^51)-(5^1+5^2+5^3+..+5^50)
4A=5^51-5^1
A=(5^51-5^1):4
![](https://rs.olm.vn/images/avt/0.png?1311)
5.415.99-4.320.89=5.230.318-229.320=229.318.(5.2-32)=229.318
5.29.619-7.229.276=5.228.319-7.229.318=228.318.(5.3-7.2)=228.318