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\(\frac{1}{2}=2\Rightarrow\frac{1}{8}=\frac{1}{2}\Rightarrow\frac{9}{8}=\frac{9}{2}\Rightarrow k=\frac{9}{2}\)
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\(\frac{1}{2}a=2b\Leftrightarrow\frac{a}{2}=2b\Leftrightarrow a=4b\left(1\right)\)
\(\frac{9}{8}a=bk\Leftrightarrow\frac{9a}{8}=bk\Leftrightarrow9a=8bk\Leftrightarrow a=\frac{8bk}{9}\left(2\right)\)
Từ (1) và (2) \(\Rightarrow4b=\frac{8bk}{9}\)
\(\Leftrightarrow4b\cdot9=8bk\)
\(\Leftrightarrow36b=8bk\)
\(\Leftrightarrow\frac{36b}{8b}=k\)
\(\Leftrightarrow k=\frac{9}{2}\)
Vậy......
Có: \(\frac{1}{2}.a=2b\Rightarrow a=4b\)
\(\frac{9}{8}.a=kb\)
\(\Rightarrow\frac{9}{8}.4b=kb\)
\(\frac{9}{2}b=kb\)
\(\Leftrightarrow k=\frac{9}{2}\)\(\left(b\ne0\right)\)
Vậy \(k=\frac{9}{2}\)
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\(\frac{1}{2}a=2b\Rightarrow a=4b\Rightarrow kb=\frac{9}{8}a=\frac{9}{8}.4b=\frac{9}{2}b\Rightarrow k=\frac{9}{2}\)
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1/2 của a=2b
=>a/2=2b=>a=4b
=>\(\frac{9}{8}.a=\frac{9}{8}.4b=\frac{36}{8}.b=kb=>k=\frac{36}{8}.b:b=\frac{36}{8}=\frac{9}{2}=4,5\)
vậy k=4,5
tick nha
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1/2 .a =2b
Nhân 2 vế với 9/4
9/8 .a = 9/4 .2b =6b .3/4 =k.3/4
=> k = 6b
Ta có :\(\frac{1}{2}a=2b\Rightarrow a=2b:\frac{1}{2}=2b\cdot2=4b\left(1\right)\)
Ta cũng có:\(\frac{9}{8}a=kb\left(2\right)\)
Thay (1) vào (2), ta có:
\(\frac{9}{8}\cdot4b=kb\)
\(\frac{9}{2}b=kb\)
\(\frac{9}{2}b:b=k\)
\(\frac{9}{2}\cdot1=k\)
\(\Rightarrow\frac{9}{2}=k\)
Vậy \(k=\frac{9}{2}\)
mình ấn kết quả đấy nhưng sai :((((