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![](https://rs.olm.vn/images/avt/0.png?1311)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\frac{x+3}{y+5}=\frac{x+5}{y+7}=\frac{\left(x+3\right)-\left(x+5\right)}{\left(y-5\right)-\left(y+7\right)}=\frac{x+3-x+5}{y+5-y+7}=\frac{3-5}{5-7}=\frac{-2}{-2}=1\)
\(\Rightarrow\frac{x+3}{y+5}=\frac{x+5}{y+7}=1\)
\(\Rightarrow\left(x+3\right).1=\left(y+5\right).1\)
\(\Rightarrow x+3=y+5\)
\(\Rightarrow x-y=5-3\)
\(\Rightarrow x-y=2\)
Vậy x - y = 2.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Rightarrow\left(x+3\right)\left(y+7\right)=\left(x+5\right)\left(y+5\right)\)
\(\Rightarrow xy+7x+3y+21=xy+5x+5y+25\)
\(\Rightarrow2x-2y=4\)
\(\Rightarrow2\left(x-y\right)=4\)
\(\Rightarrow x-y=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x+3}{y+5}=\frac{x+5-x-3}{y+7-y-5}\frac{2}{2}=1\)
x + 3 = y + 5 => x - y = 5 - 3 = 2
vậy x - y = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x+3}{y+5}=\frac{x+5}{y+7}=\frac{x+5-x-3}{y+7-y-5}=\frac{2}{2}=1\)
=> x+3 = y+5
=> x -y = 5 -3 =2
Vậy x -y =2
![](https://rs.olm.vn/images/avt/0.png?1311)
=>x+3 =y+5
=> x -y =5-3
x-y =2 ( do mạng lag = thóat ra)
b) => 6x -7 =0 => x = 7/6
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
=>(x+3)(y+7)=(y+5)(x+5)
x(y+7)+3(y+7)=y(x+5)+5(x+5)
xy+7x+3y+21=xy+5y+5x+25
(xy-xy)+(7x-5x)=(5y-3y)+(25-21)
2x=2y+4
2x-2y=4
2(x-y)=4
x-y=4/2
x-y=2
![](https://rs.olm.vn/images/avt/0.png?1311)
=> \(\left(x+3\right)\left(y+7\right)=\left(y+5\right)\left(x+5\right)\)
=> \(xy+7x+3y+3\cdot7=xy+5y+5x+5\cdot5\)
=> \(xy+7x+3y+21=xy+5y+5x+25\)
=> \(xy+7x+3y+21-xy-5y-5x-25=0\)
=> \(xy+7x+3y-xy-5y-5x=-21+25\)
=> \(2x-2y=4\)
=> \(2\left(x-y\right)=4\)
=> \(x-y=4:2\)
=> \(x-y=2\)
tick cho mình nha
Áp dụng t/c dãy tỉ số bằng nhau : \(\frac{x+3}{y+5}=\frac{x+5}{y+7}=\frac{\left(x+5\right)-\left(x+3\right)}{\left(y+7\right)-\left(y+5\right)}=\frac{2}{2}=1\)
\(\Rightarrow x+3=y+5\Rightarrow x-y=5-3=2\)
Áp dụng tính chất dãy tỉ số bằng nhau :\(\frac{x+3}{y+5}\)=\(\frac{x+5}{y+7}\) =\(\frac{\left(x+5\right)-\left(x+3\right)}{\left(x+7\right)-\left(y+5\right)}\)=\(\frac{2}{2}\)=1
\(\Rightarrow\)x+3 = y +5
\(\Rightarrow\)x -y = 5-3=2