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Giải:
a)\(\dfrac{3}{4}x-\dfrac{1}{3}=\dfrac{-5}{6}\)
\(\dfrac{3}{4}x=\dfrac{-5}{6}+\dfrac{1}{3}\)
\(\dfrac{3}{4}x=\dfrac{-1}{2}\)
\(x=\dfrac{-1}{2}:\dfrac{3}{4}\)
\(x=\dfrac{-2}{3}\)
b)\(\left(2\dfrac{4}{5}x-0,2\right):\dfrac{4}{5}=\dfrac{7}{8}\)
\(\dfrac{14}{5}x-\dfrac{1}{5}=\dfrac{7}{8}.\dfrac{4}{5}\)
\(\dfrac{14}{5}x-\dfrac{1}{5}=\dfrac{7}{10}\)
\(\dfrac{14}{5}x=\dfrac{7}{10}+\dfrac{1}{5}\)
\(\dfrac{14}{5}x=\dfrac{9}{10}\)
\(x=\dfrac{9}{10}:\dfrac{14}{5}\)
\(x=\dfrac{9}{28}\)
c) \(\dfrac{1}{4}+\dfrac{1}{3}:\left|2x-1\right|=\dfrac{11}{12}\)
\(\dfrac{1}{3}:\left|2x-1\right|=\dfrac{11}{12}-\dfrac{1}{4}\)
\(\dfrac{1}{3}:\left|2x-1\right|=\dfrac{2}{3}\)
\(\left|2x-1\right|=\dfrac{1}{3}:\dfrac{2}{3}\)
\(\left|2x-1\right|=\dfrac{1}{2}\)
⇒2x-1=\(\dfrac{1}{2}\) hoặc 2x-1=\(\dfrac{-1}{2}\)
x=\(\dfrac{3}{4}\) hoặc x=\(\dfrac{1}{4}\)
câu a nha \(\dfrac{3}{4}x-\dfrac{1}{3}=-\dfrac{5}{6}\)
\(\dfrac{3}{4}x=-\dfrac{5}{6}+\dfrac{1}{3}\)
\(\dfrac{3}{4}x=-\dfrac{3}{6}\)
\(x=-\dfrac{3}{6}:\dfrac{3}{4}\)
\(x=-\dfrac{6}{4}.\dfrac{4}{3}\)
\(x=-\dfrac{24}{12}=-2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1: \(x=\dfrac{-1}{2}+\dfrac{3}{4}=\dfrac{-2}{4}+\dfrac{3}{4}=\dfrac{1}{4}\)
2: x-1/5=2/11
nên \(x=\dfrac{2}{11}+\dfrac{1}{5}=\dfrac{10}{55}+\dfrac{11}{55}=\dfrac{21}{55}\)
3: \(x-\dfrac{5}{6}=\dfrac{16}{42}-\dfrac{8}{56}=\dfrac{5}{21}\)
nên \(x=\dfrac{5}{21}+\dfrac{5}{6}=\dfrac{10}{42}+\dfrac{35}{42}=\dfrac{45}{42}=\dfrac{15}{14}\)
4: \(\dfrac{x}{5}=\dfrac{5}{6}-\dfrac{19}{30}=\dfrac{25}{30}-\dfrac{19}{30}=\dfrac{6}{30}=\dfrac{1}{5}\)
nên x=1
9: x-7/8=13/12
nên \(x=\dfrac{13}{12}+\dfrac{7}{8}=\dfrac{26}{24}+\dfrac{21}{24}=\dfrac{47}{24}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{1}{4}+\dfrac{x}{12}=\dfrac{8}{12}\)
\(\dfrac{3}{12}+\dfrac{x}{12}=\dfrac{8}{12}\)
\(\dfrac{3+x}{12}=\dfrac{8}{12}\)
\(\dfrac{x+3}{12}=\dfrac{8}{12}\)
\(=\)\(\dfrac{5}{12}\)
Vậy \(x=5\).
![](https://rs.olm.vn/images/avt/0.png?1311)
`2/(3.5) + 2/(5.7) + 2/(7.9) + .... + 2/(37.39)`
`=2 . (1/(3.5) + 1/(5.7) + .... + 1/(37.39)`
`=2 .[ 1/2 .(1/3 -1/5 + 1/5 -1/7 +....+1/37 -1/39)]`
`= 1/3 - 1/39`
`=4/13`
![](https://rs.olm.vn/images/avt/0.png?1311)
c) Ta có: \(\dfrac{5}{9}\cdot\dfrac{7}{13}-\dfrac{30}{23}+\dfrac{6}{9}\cdot\dfrac{5}{13}+\dfrac{7}{23}\)
\(=\dfrac{5}{13}\cdot\dfrac{7}{9}+\dfrac{6}{9}\cdot\dfrac{5}{13}-\dfrac{30}{23}+\dfrac{7}{23}\)
\(=\dfrac{5}{13}\left(\dfrac{7}{9}+\dfrac{6}{9}\right)-1\)
\(=\dfrac{5}{13}\cdot\dfrac{13}{9}-1\)
\(=\dfrac{-4}{9}\)
d) Ta có: \(\left(-3.2\right)\cdot\dfrac{-15}{64}+\left(0.8-2\dfrac{4}{5}\right):3\dfrac{2}{3}\)
\(=\dfrac{16}{5}\cdot\dfrac{15}{64}+\left(\dfrac{4}{5}-\dfrac{14}{5}\right):\dfrac{11}{3}\)
\(=\dfrac{3}{4}-2:\dfrac{11}{3}\)
\(=\dfrac{3}{4}-2\cdot\dfrac{3}{11}\)
\(=\dfrac{3}{4}-\dfrac{6}{11}=\dfrac{33}{44}-\dfrac{24}{44}=\dfrac{9}{44}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)