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đk : x khác -3
\(\left(x+3\right)^2=36\Leftrightarrow\left[{}\begin{matrix}x+3=6\\x+3=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-9\end{matrix}\right.\left(tm\right)\)
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3²ˣ⁺¹ - 20 = 7
3²ˣ⁺¹ = 7 + 20
3²ˣ⁺¹ = 27
3²ˣ⁺¹ = 3³
2x + 1 = 3
2x = 3 - 1
2x = 2
x = 2 : 2
x = 1
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(27 + 29) + (86 - 84) + 5
= 56 + 2 + 5
= 63
Chúc bạn học tốt!! ^^
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\(A=\left(1+3+3^2\right)+...+\left(3^{99}+3^{100}+3^{101}\right)\\ A=\left(1+3+3^2\right)+...+3^{99}\left(1+3+3^2\right)\\ A=\left(1+3+3^2\right)\left(1+...+3^{99}\right)=13\left(1+...+3^{99}\right)⋮13\)
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\(-\left(-x\right):\left(-15\right).2=16\)
\(\Rightarrow x:\left(-15\right)=8\)
\(\Rightarrow x=-120\)
Vậy: \(x=-120\)
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Ta có : (2x - 1)3 = 125
=> (2x - 1)3 = 53
=> 2x - 1 = 5
=> 2x = 5 + 1
=> 2x = 6
=> x = 6 : 2
=> x = 3
( 2x - 1 )3 = 125
ta có :
(2x - 1)3 = 53
=> 2x - 1 = 5
2x = 5 + 1
2x = 6
x = 6 : 2
x = 3
VẬY x = 3
đk : x khác 2/5
\(\dfrac{3}{5x-2}=\dfrac{1}{36}\Rightarrow5x-2=108\Leftrightarrow x=22\left(tm\right)\)
b) \(\frac{3}{5x-2}=\frac{13}{36}-\frac{1}{3}\)
\(\Rightarrow\frac{3}{5x-2}=\frac{1}{36}\)
\(\Rightarrow\frac{3}{5x-2}=\frac{3}{108}\)
\(\Rightarrow5x-2=108\)
\(\Rightarrow5x=108+2\)
\(\Rightarrow5x=110\)
\(\Rightarrow x=110:5\)
\(\Rightarrow x=22\)
b) \(\frac{x+3}{12}=\frac{3}{x+3}\)
\(\Rightarrow2\left(x+3\right)=12\cdot3\)
\(\Rightarrow x+3=12:2\cdot3\)
\(\Rightarrow x+3=6\cdot3\)
\(\Rightarrow x+3=18\)
\(\Rightarrow x=18-3\)
\(\Rightarrow x=15\)