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\(f,=\left(5^2+3\right):7=28:7=4\\ g,=7^2-9+8\cdot25=49-9+200=240\\ h,=600+72+18=690\\ i,=5^2+5-20=10\\ j,=45-28+83=100\)
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\(2A=\frac{4}{1.5}+\frac{6}{5.11}+\frac{8}{11.19}+\frac{10}{19.29}+\frac{12}{29.41}\)
\(=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{11}+\frac{1}{11}-\frac{1}{19}+...+\frac{1}{29}-\frac{1}{41}=1-\frac{1}{41}=\frac{40}{41}\)
\(\Rightarrow A=\frac{20}{21}\)
\(3B=\frac{3}{1.4}+\frac{6}{4.10}+\frac{9}{10.19}+\frac{12}{19.31}=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{10}+\frac{1}{10}-\frac{1}{19}+\frac{1}{19}-\frac{1}{31}\)
\(=1-\frac{1}{31}=\frac{30}{31}\)
\(\Rightarrow B=\frac{10}{31}=\frac{20}{62}<\frac{20}{41}\)
Do đó $A>B$
Ta có: \(A=\dfrac{2}{1.5}+\dfrac{3}{5.11}+\dfrac{4}{11.19}+\dfrac{5}{19.29}+\dfrac{6}{29.41}\)
\(2A=1-\dfrac{1}{5}+\dfrac{1}{5}+...+\dfrac{1}{29}-\dfrac{1}{41}\)
\(2A=1-\dfrac{1}{41}=\dfrac{40}{41}\)
\(A=\dfrac{20}{41}\)
Lại có: \(B=\dfrac{1}{1.4}+\dfrac{2}{4.10}+\dfrac{3}{10.19}+\dfrac{4}{19.31}\)
\(3B=\dfrac{3}{1.4}+\dfrac{6}{4.10}+\dfrac{9}{10.19}+\dfrac{12}{19.31}\)
\(3B=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{10}+...+\dfrac{1}{19}-\dfrac{1}{31}\)
\(3B=1-\dfrac{1}{31}=\dfrac{30}{31}\)
\(B=\dfrac{10}{31}\)
Vì \(\dfrac{20}{41}>\dfrac{10}{31}\) nên...
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gọi d là ƯCLN(18n+3,21n+7)
ta có 18n+3chia hết cho d
21n+7 chia hết cho d
⇔21n+7-18n-3 chia hết cho d
⇔126n+42-126n-21 chia hết cho d
21 chia hết cho d
⇒d∈Ư(21)=1;3;7;21
n ≠ 3k-1;3k-3;3k-7;3k-21
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\(3n-2\inƯ\left(15\right)\) \(=\left\{1;-1;3;-3;5;-5;15;-15\right\}.\)
\(\Leftrightarrow n\in\left\{1;\dfrac{1}{3};\dfrac{5}{3};\dfrac{-1}{3};\dfrac{7}{3};-1;\dfrac{17}{3};\dfrac{-13}{3}\right\}.\)
Mà \(n\ne\dfrac{2}{3};n\in Z.\)
\(\Rightarrow n\in\left\{1;-1\right\}.\)
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Bài 1:
a: =34,59
b: =56,13
c: =47,31
d: =58,30
Câu 2:
a: =380
b: =483
c: =7540
d: =4920
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1:
1: \(A=\dfrac{3}{14}+\dfrac{2}{7}-\dfrac{3}{7}=\dfrac{3}{14}-\dfrac{1}{7}=\dfrac{3}{14}-\dfrac{2}{14}=\dfrac{1}{14}\)
2: \(\Leftrightarrow-\dfrac{2}{3}\cdot x=-\dfrac{2}{3}\)
=>x=1
3:
a: Cùng phía với điểm I: C,K,B
b: Tia đối của tia CK là CI hoặc CA
c: AC=2*1=2cm
=>CB=8-2=6cm
KB=6/2=3cm
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3x-27=4x3 mũ 2
3x-27=4x9
3x-27=36
3x=36+27
3x=63
x=63:3
x=21