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\(25^{2n}:5^n=125\)
\(\left(5^2\right)^{2n}:5^n=5^3\)
\(5^{2.2n}:5^n=5^3\)
\(5^{4n-n}=5^3\)
\(5^{3n}=5^3\)
\(3n=3\)
\(n=3:3\)
\(n=1\)
\(\Leftrightarrow5^{4n}:5^n=125\)
=>5^3n=5^3
=>3n=3
=>n=1
Đề: Tìm x
\(3-\left(x+2\frac{1}{2}-3\frac{1}{4}\right):16\frac{1}{2}=2\)
\(\left(x+\frac{5}{2}-\frac{13}{4}\right):\frac{33}{2}=3-2\)
\(\left(x+\frac{10}{4}-\frac{13}{4}\right):\frac{33}{2}=1\)
\(x+\frac{-3}{4}=\frac{33}{2}\)
\(x=\frac{33}{2}+\frac{3}{4}\)
\(x=\frac{66}{4}+\frac{3}{4}\)
\(x=\frac{69}{4}\)
Vậy \(x=\frac{69}{4}.\)
Bài 1.
\(a,\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{4}{12}+\dfrac{3}{12}=\dfrac{7}{12}\)
\(b,\dfrac{-2}{5}+\dfrac{7}{21}=\dfrac{-42}{105}+\dfrac{35}{105}=\dfrac{-77}{105}=\dfrac{-11}{15}\)
\(c,\dfrac{3}{8}+\dfrac{-5}{6}=\dfrac{18}{48}+\dfrac{-40}{48}=\dfrac{-22}{48}=\dfrac{-11}{24}\)
\(d,\dfrac{-3}{4}+\dfrac{2}{5}=\dfrac{-15}{20}+\dfrac{8}{20}=\dfrac{-7}{20}\)
\(e,\dfrac{1}{6}+\dfrac{-3}{2}=\dfrac{2}{12}+\dfrac{-18}{12}=\dfrac{16}{12}=\dfrac{4}{3}\)
\(f,\dfrac{-2}{5}+\dfrac{-4}{3}=\dfrac{-6}{15}+\dfrac{-20}{15}=\dfrac{-26}{15}\)
\(g,\dfrac{1}{8}+\dfrac{-3}{4}=\dfrac{4}{32}+\dfrac{-24}{32}=\dfrac{20}{32}=\dfrac{5}{8}\)
\(h,\dfrac{-3}{4}+\dfrac{3}{7}=\dfrac{-21}{28}+\dfrac{12}{28}=\dfrac{-9}{28}\)
\(i,\dfrac{-3}{4}+\dfrac{-4}{5}=\dfrac{-15}{20}+\dfrac{-16}{20}=\dfrac{-31}{20}\)
\(k,\dfrac{-5}{25}+\dfrac{-7}{14}=\dfrac{-70}{350}+\dfrac{-175}{350}=\dfrac{-245}{350}=\dfrac{-7}{10}\)
\(l,\dfrac{6}{21}+\dfrac{-3}{15}=\dfrac{90}{315}+\dfrac{-63}{315}=\dfrac{27}{315}=\dfrac{3}{35}\)
\(m,\dfrac{3}{4}-\dfrac{5}{8}+\dfrac{1}{2}=\dfrac{24}{32}-\dfrac{20}{32}+\dfrac{1}{2}=\dfrac{4}{32}+\dfrac{1}{2}=\dfrac{1}{8}+\dfrac{1}{2}=\dfrac{2}{16}+\dfrac{8}{16}=\dfrac{10}{16}=\dfrac{5}{8}\)
\(n,\dfrac{-3}{12}-\dfrac{1}{-4}+\dfrac{-2}{6}=\dfrac{-1}{4}-\dfrac{1}{-4}+\dfrac{-1}{3}=0+\dfrac{-1}{3}=\dfrac{-1}{3}\)
\(p,\dfrac{1}{3}+\dfrac{-3}{4}-\dfrac{5}{12}=\dfrac{4}{12}+\dfrac{-9}{12}-\dfrac{5}{12}=\dfrac{-5}{12}-\dfrac{5}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}\)
Bài 2:
\(a,\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}-\dfrac{3}{5}\)
\(x=\dfrac{7}{30}\)
\(b,x-\dfrac{1}{4}=\dfrac{-5}{8}\)
\(x=\dfrac{-5}{8}+\dfrac{1}{4}\)
\(x=\dfrac{-3}{8}\)
\(c,x-\dfrac{2}{3}=\dfrac{7}{12}\)
\(x=\dfrac{7}{12}+\dfrac{2}{3}\)
\(x=\dfrac{5}{4}\)
\(d,x+\dfrac{-7}{15}=-1\dfrac{1}{20}\)
\(x=-1\dfrac{1}{20}-\dfrac{-7}{15}\)
\(x=\dfrac{-7}{12}\)
\(e,x-\dfrac{1}{2}=\dfrac{-3}{4}\)
\(x=\dfrac{-3}{4}+\dfrac{1}{2}\)
\(x=\dfrac{-1}{4}\)
\(f,x-\dfrac{3}{4}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{3}{4}\)
\(x=\dfrac{5}{4}\)
\(g,x-\dfrac{1}{4}=\dfrac{5}{8}\cdot\dfrac{2}{3}\)
\(x-\dfrac{1}{4}=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}+\dfrac{1}{4}\)
\(x=\dfrac{2}{3}\)
\(h,\dfrac{4}{5}-x=\dfrac{-8}{35}\)
\(x=\dfrac{4}{5}-\dfrac{-8}{35}\)
\(x=\dfrac{36}{35}\)
#YVA
tìm x;y nguyên để biểu thức nguyên đúng ko bạn ?
\(\Rightarrow x;y-1\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
x | 1 | -1 | 7 | -7 |
y-1 | 7 | -7 | 1 | -1 |
y | 8 | -6 | 2 | 0 |
21. 0,1 [4 -(-3,2 - 4,8)] : 0,1
= 21. 0,1 [4 - (-8)] : 0,1
= 21.0,1. 12 : 0,1
= 2,1. 12 : 0,1
=252
\(21.0,1[ 4 - ( -3,2 - 4,8 )] : 0,1\)
\(= 2,1 . [ 4 - ( -8 )] . 10\)
\(= 2,1 . 10 . 12\)
\(= 21.12\)
\(= 252\)
Bằng 0 chứ nhỉ em ?
(x-5) . (2x-4)= 0
\(\left[{}\begin{matrix}x-5=0\\2x-4=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=5\\2x=4\end{matrix}\right.< =>\left[{}\begin{matrix}x=5\\x=2\end{matrix}\right.\)
(x-5) . (2x-4)= 5
<=> 2x^2 - 4x - 10x + 20 = 5
<=> 2x^2 - 14x + 15 = 0
Giải pt bâc hai ra đc : \(x=\dfrac{7+\sqrt{19}}{2}\)và \(x2=\dfrac{7-\sqrt{19}}{2}\)
=>x(x^2-9/16)=0
=>x(x-3/4)(x+3/4)=0
=>x=0; x=3/4; x=-3/4