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=>5(7x-1)+60x=6(16-x)
=>35x-5+60x-96+6x=0
=>101x=101
hay x=1
\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)
\(\Leftrightarrow\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\)
\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)
\(\Leftrightarrow35x-5+60x=96-6x\)
\(\Leftrightarrow95x-5-96+6x=0\)
\(\Leftrightarrow101x-101=0\\ \Leftrightarrow101x=101\\ \Leftrightarrow x=1\)
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a: \(\Leftrightarrow x-5-2\left(2x-1\right)< 12\)
=>x-5-4x+2<12
=>-3x-3<12
=>-3x<15
hay x>-5
b: \(\Leftrightarrow4\left(5x^2-3\right)+5\left(3x-1\right)>10x\left(2x+3\right)-100\)
\(\Leftrightarrow20x^2-12+15x-5-20x^2-30x+100>0\)
=>-15x+83>0
hay x<83/15
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=>5(7x-1)+60x=6(16-x)
=>35x-5+60x=96-6x
=>95x-5=96-6x
=>101x=101
=>x=1
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a: =>10x-14=15-9x
=>19x=29
hay x=29/19
b: \(\Leftrightarrow3\left(10x+3\right)=36+4\left(8x+6\right)\)
=>30x+9=36+32x+24
=>30x+9=32x+60
=>-2x=51
hay x=-51/2
c: \(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)
=>35x-5+60x=96-6x
=>101x=101
hay x=1
d: \(\Leftrightarrow12\left(\dfrac{1}{2}-\dfrac{3}{2}x\right)=-5x+6\)
\(\Leftrightarrow6-18x+5x-6=0\)
=>-13x=0
hay x=0
\(a,\dfrac{5x-7}{3}=\dfrac{5-3x}{2}\\ \Leftrightarrow2\left(5x-7\right)=3\left(5-3x\right)\\ \Leftrightarrow10x-14=15-9x\\ \Leftrightarrow10x-14-15+9x=0\\ \Leftrightarrow19x-19=0\\ \Leftrightarrow x=1\)
\(b,\dfrac{10x+3}{12}=1+\dfrac{6+8x}{9}\\ \Leftrightarrow\dfrac{3\left(10x+3\right)}{36}=\dfrac{36}{36}+\dfrac{4\left(6+8x\right)}{36}\\ \Leftrightarrow30x+9=36+24+32x\\ \Leftrightarrow36+24+32x-30x-9=0\\ \Leftrightarrow2x+51=0\\ \Leftrightarrow x=-\dfrac{51}{2}\)
\(c,\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\\ \Leftrightarrow\dfrac{7x-1+12x}{6}=\dfrac{16-x}{5}\\ \Leftrightarrow5\left(19x-1\right)=6\left(16-x\right)\\ \Leftrightarrow95x-5=96-6x\\ \Leftrightarrow95x-5-96+6x=0\\ \Leftrightarrow101x-101=0\\ \Leftrightarrow x=1\)
\(d,4\left(0,5-1,5x\right)=-\dfrac{5x-6}{3}\\ \Leftrightarrow12\left(0,5-1,5x\right)=6-5x\\ \Leftrightarrow6-18x=6-5x\\ \Leftrightarrow6-5x-6+18x=0\\ \Leftrightarrow13x=0\\ \Leftrightarrow x=0\)
`[ 7x - 1 ] / 6 + 2x >= [ 16 - x ] / 5`
`<=> [ 5 ( 7x - 1 ) + 60x ] / 30 >= [ 6 ( 16 - x ) ] / 30`
`<=> 35x - 5 + 60x >= 96 - 6x`
`<=>101x >= 101`
`<=> x >= 1`
Vậy `S = { x | x >= 1 }`