![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,(x+1)-(x+2)-(x+3)=24
=>x+1-x-2-x-3 =24
=>(x-x-x)+(1-2-3) =24
=> -x-4 =24
=> -x =24+4
=> -x =28
=> x =-28
Vậy x=-28
b,4x+2-3(x-1)=3x-5
=>4x+2-3x+3=3x-5
=>3x-4x+3x =2+3+5
=>2x =10
=>x =5
Vậy x=5
c,x-1-2(x-2)=x-11
=>x-1-2x+4=x-11
=>x-2x-x =-11+1-4
=>-2x =-14
=>x =7
Vậy x = 7
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x}{12}=\frac{-3}{9}\)
\(\Rightarrow x=\frac{-3}{9}.12=-4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: Ta có: \(2x+10=4^5:4^3\)
\(\Leftrightarrow2x=6\)
hay x=3
b: Ta có: \(70-5\left(x-3\right)=45\cdot2022^0\)
\(\Leftrightarrow x-3=5\)
hay x=8
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(x-17=19\)
\(\Leftrightarrow x=36\).
b) \(126⋮x,90⋮x,x>2\)
\(126⋮x,90⋮x\Rightarrow x\inƯ\left(ƯCLN\left(90,126\right)\right)\)
Ta có: \(126=2.3^2.7\), \(90=2.3^2.5\).
\(\RightarrowƯCLN\left(90,126\right)=2.3^2=18\).
\(\Rightarrow x\inƯ\left(18\right)\)mà \(x>2\)nên \(x\in\left\{3,6,9,18\right\}\).
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
2/35 + 4/77 + 2/143 + 4/221 + 2/323 + 4/437 + 2/575
= 2/5.7 + 4/7.11 + 2/11.13 + 4/13.17 + 2/17.19 + 4/19.23 + 2/23.25
= 1/5 - 1/7 + 1/7 - 1/11 + 1/11 - 1/13 + 1/13 - 1/17 + 1/17 - 1/19 + 1/19 - 1/23 + 1/23 - 1/15
= 1/5 - 1/25
= 4/25
\(\frac{2}{35}\)+ \(\frac{4}{77}\)+ \(\frac{2}{143}\)+ \(\frac{4}{221}\)+ \(\frac{2}{323}\)+ \(\frac{4}{437}\)+ \(\frac{2}{575}\).
= \(\frac{2}{5.7}\)+ \(\frac{4}{7.11}\)+ \(\frac{2}{11.13}\)+ \(\frac{4}{13.17}\)+ \(\frac{4}{17.21}\)+ \(\frac{2}{21.23}\).
= \(\frac{1}{5}\)- \(\frac{1}{7}\)+ \(\frac{1}{7}\)- \(\frac{1}{11}\)+ \(\frac{1}{11}\)- \(\frac{1}{13}\)+ \(\frac{1}{13}\)- \(\frac{1}{17}\)+ \(\frac{1}{17}\)- \(\frac{1}{21}\)+ \(\frac{1}{21}\)- \(\frac{1}{23}\).
= \(\frac{1}{5}\)- \(\frac{1}{23}\).
= \(\frac{23}{115}\)- \(\frac{5}{115}\).
= \(\frac{18}{115}\).
![](https://rs.olm.vn/images/avt/0.png?1311)