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\(\frac{25.18.48}{12.15.24}\)
\(=\frac{5^2.2.3^2.2^4.3}{2^2.3.3.5.2^3.3}\)
\(=\frac{5^2.2^5.3^3}{5.2^6.3^3}\)
\(=\frac{5}{2}\)
\(\frac{25x18x48}{12x15x24}\)= \(\frac{\left(5x5\right)x\left(3x6\right)x\left(24x2\right)}{\left(2x6\right)x\left(3x5\right)x24}\)= \(\frac{5x3x2}{2x3}\)= 5
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\(\frac{25.18.48}{12.15.24}=\frac{5.5.2.3.3.24.2}{2.2.3.5.3.24}\)
\(=\frac{5.5}{5}=5\)
\(\frac{25\times18\times48}{12\times15\times24}\)
\(=\frac{5\times3\times2}{2\times3\times1}\)
\(=\frac{5}{1}=5\)
>Bạn học tốt nhé<
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Trả lời:
\(\frac{25.18.48}{12.15.24}=\frac{5.3.2}{2.3.1}=\frac{5}{1}=5\)
Hok tốt!
_ _ _ _ _
\(\frac{25x18x48}{12x15x24}\)= \(\frac{5x5x6x3x12x4}{12x5x3x6x4}\)= 5
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\(\frac{\frac{1}{4}+\frac{1}{24}+\frac{1}{124}}{\frac{3}{4}+\frac{3}{24}+\frac{3}{124}}+\frac{\frac{2}{7}+\frac{2}{17}+\frac{2}{127}}{\frac{3}{7}+\frac{3}{17}+\frac{3}{127}}=\frac{\frac{1}{4}+\frac{1}{24}+\frac{1}{124}}{3\left(\frac{1}{4}+\frac{1}{24}+\frac{1}{124}\right)}+\frac{2\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{127}\right)}{3\left(\frac{1}{7}+\frac{1}{17}+127\right)}=\frac{1}{3}+\frac{2}{3}=\) \(1\)
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Gọi a là tử số, b là mẫu số của phân số A
a = \(\frac{2008}{1}\)+ \(\frac{2007}{2}\)+ \(\frac{2006}{3}\)+ ... + \(\frac{1}{2008}\)
Dãy số a có (2008 - 1) : 1 + 1 = 2008 số. Và a = ( \(\frac{2008}{1}\)+ \(\frac{1}{2008}\)) x (2008 : 2)
b = \(\frac{1}{2}\)+ \(\frac{1}{3}\)+ \(\frac{1}{4}\)+ ... + \(\frac{1}{2009}\)
Dãy số b có (2009 - 2) : 1 + 1 = 2008 số. Và b = (\(\frac{1}{2}\)+ \(\frac{1}{2009}\)) x (2008 : 2)
A = [ ( \(\frac{2008}{1}\)+ \(\frac{1}{2008}\)) x (2008 : 2)] : [ (\(\frac{1}{2}\)+ \(\frac{1}{2009}\)) x (2008 : 2)] = ( \(\frac{2008}{1}\)+ \(\frac{1}{2008}\)) : (\(\frac{1}{2}\)+ \(\frac{1}{2009}\))
A = \(\frac{\text{2008 x2008 + 1}}{2008}\)x \(\frac{2x2009+2}{2x2009}\)
A = 2008
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a) 5/30+15/90+25/150+35/210+45/270
=1/6+1/6+1/6+1/6+1/6
=1/6 x 5
=5/6
b) 1/2+1/6+1/12+1/20+....+1/56
=1/1x2+1/2x3+1/3x4+1/4x5+.....1/7x8
=1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.......-1/7+1/7-1/8
=1/1-1/8
=7/8
c) mình chịu
\(\frac{25x18x48}{12x15x48}=\frac{25x18}{12x15}=\frac{5x9}{6x3}=\frac{5x3}{6}\)
\(=\frac{15}{6}=\frac{5}{2}\)
\(\frac{25\times18\times48}{12\times15\times48}=\frac{25\times18}{12\times15}\)
\(=\frac{5\times5\times3\times6}{6\times2\times3\times5}\)
\(=\frac{5}{2}\)