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\(x+\frac{3+\frac{3}{20}+\frac{3}{13}+\frac{3}{2013}}{5+\frac{5}{20}+\frac{5}{13}+\frac{5}{2013}}=\frac{9}{2}\)
\(x+\frac{3\times\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}{5\times\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}=\frac{9}{2}\)
\(x+\frac{3}{5}=\frac{9}{2}\)
\(x=\frac{39}{10}\)
\(x=3,9\)
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\(=3.\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{9900}\right)\)
\(=3.\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\right)\)
\(=3.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\right)\)
\(=3.\left(1-\frac{1}{100}\right)\)
\(=3.\frac{99}{100}=\frac{297}{100}\)
\(\frac{3}{2}+\frac{3}{6}+\frac{3}{12}+...+\frac{3}{9900}\\ =3\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\right)\)
\(=3\left(\frac{2-1}{1.2}+\frac{3-2}{2.3}+...+\frac{100-99}{99.100}\right)\\ =3\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\right)\)
\(=3\left(1-\frac{1}{100}\right)=3.\frac{99}{100}=\frac{297}{100}\)
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\(\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right).\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}=\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right).\frac{12}{49}}{\frac{10}{3}+\frac{2}{9}}=\frac{\left(\frac{13}{20}-\frac{1}{5}\right).\frac{12}{49}}{\frac{32}{9}}=\frac{\frac{9}{20}.\frac{12}{49}}{\frac{32}{9}}=\frac{\frac{27}{245}}{\frac{32}{9}}=\frac{243}{7840}\)
Có đúng không vu bao quynh?
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đề bài là:(3/20+1/2-1/5)-12/49 phần 10/3 dổi từ3mot phan ba +2/9 đúng ko
\(\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right)-\frac{12}{49}=\left(\frac{3}{20}+\frac{10}{20}-\frac{4}{20}\right)-\frac{12}{49}=\frac{9}{20}-\frac{12}{49}=\frac{201}{980}\)
\(3\frac{1}{3}+\frac{2}{9}=\frac{10}{3}+\frac{2}{9}=\frac{30}{9}+\frac{2}{9}=\frac{32}{9}\)
tick đúng cho mk nha tran Thi Thanh Hong 01
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=4
Chính xác 100%.k cho mình nha bạn!!Chúc bạn học tốt!!!
\(\frac{20}{16}\)+\(\frac{3}{15}\)+\(\frac{2}{12}\)+\(\frac{3}{4}\)+\(\frac{4}{5}\)+\(\frac{5}{6}\)= (\(\frac{20}{16}\)+\(\frac{3}{4}\) )+( \(\frac{3}{15}\)+ \(\frac{4}{5}\) )+( \(\frac{2}{12}\)+ \(\frac{5}{6}\) )
= 2+1+1 = 4
Chúc bạn học tốt !!!
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Ta có phần tử \(=\frac{1}{19}+\frac{2}{18}+\frac{3}{17}+...+\frac{18}{2}+\frac{19}{1}\)
\(=\left(\frac{1}{19}+1\right)+\left(\frac{2}{18}+1\right)+...+\left(\frac{18}{2}+1\right)+\left(\frac{19}{1}+1\right)-19\)
\(=\frac{20}{19}+\frac{20}{18}+...+\frac{20}{2}+\frac{20}{1}+\frac{20}{20}-20\)
\(=20.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{19}+\frac{1}{20}\right)\left(1\right)\)
Thay (1) vào P ta được :
\(P=\frac{20.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{20}\right)}{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{20}}\)
\(=20\)
Bài làm
\(\frac{2}{3}+\frac{20}{3}=\frac{2+20}{3}=\frac{22}{3}\)
\(\frac{2}{3}+\frac{20}{3}=\frac{2+20}{3}\)
\(=\frac{22}{3}\)
hok tốt