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11 tháng 2 2017
\(a.\frac{x}{7}=\frac{x+16}{35}\)
\(\Rightarrow35x=7\left(x+16\right)\)
\(\Rightarrow35x=7x+112\)
\(\Rightarrow35x-7x=112\)
\(\Rightarrow28x=112\)
\(\Rightarrow x=112:28\)
\(\Rightarrow x=4\)
\(b.\frac{2-x}{16}=\frac{-4}{x-2}\)
\(\Rightarrow\frac{-\left(x-2\right)}{16}=\frac{-4}{x-2}\)
\(\Rightarrow\frac{x-2}{16}=\frac{4}{x-2}\)
\(\Rightarrow\left(x-2\right)^2=4.16\)
\(\Rightarrow\left(x-2\right)^2=64\)
\(\Rightarrow\left(x-2\right)^2=\left(\pm8\right)^2\)
\(\Rightarrow x-2=8\) hoặc \(x-2=-8\)
+) Nếu \(x-2=8\)
\(\Rightarrow x=8+2\)
\(\Rightarrow x=10\)
+) Nếu \(x-2=-8\)
\(\Rightarrow x=-8+2\)
\(\Rightarrow x=-6\)
Vậy \(x=10;x=-6\)
DQ
2
16 tháng 8 2018
34 +14 :x=−2
\(\frac{1}{4}:x=-2-\frac{3}{4}\)
\(\frac{1}{4}:x=\frac{-11}{4}\)
\(x=\frac{1}{4}:\frac{-11}{4}\)
\(x=\frac{-1}{11}\)
x2:1611 =114
tìm x
KD
16 tháng 8 2018
\(\frac{3}{4}+\frac{1}{4}:x=-2\)
\(\frac{1}{4}:x=-2-\frac{3}{4}\)
\(\frac{1}{4}:x=\frac{-11}{4}\)
\(x=\frac{1}{4}:\frac{-11}{4}\)
\(x=\frac{-1}{11}\)
\(x^2:\frac{16}{11}=\frac{11}{4}\)
\(x^2=\frac{11}{4}\times\frac{16}{11}\)
\(x^2=4\)
\(\Rightarrow x=-2\)\(\text{hoặc}\)\(x=2\)
CL
0
NN
3
29 tháng 7 2019
\(\frac{1}{2}\times+\frac{1}{4}\times+\frac{1}{8}\times=\frac{1}{16}\)
\(\Rightarrow\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)\times=\frac{1}{16}\)
\(\Rightarrow\frac{7}{8}\times=\frac{1}{16}\)
\(\Rightarrow\times=\frac{1}{14}\)
29 tháng 7 2019
\(\frac{1}{2}x+\frac{1}{4}x+\frac{1}{8}x=\frac{1}{16}\)
\(\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)x=\frac{1}{16}\)
\(\frac{7}{8}x=\frac{1}{16}\)
\(x=\frac{1}{16}\div\frac{7}{8}\)
\(x=\frac{1}{14}\)
2 tháng 8 2016
a) \(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{\left(3.2^2.2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{\left(3.2^{18}\right)^2}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{9.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2^{36}}{2^{35}.9}=2\)
b) \(\frac{3}{2}.x-\left(\frac{4}{5}-2.x\right)=1\frac{3}{10}:\frac{3}{2}\)
\(\frac{3}{2}.x-\frac{4}{5}+2.x=\frac{13}{10}:\frac{3}{2}\)
\(\left(\frac{3}{2}.x+2.x\right)-\frac{4}{5}=\frac{13}{10}.\frac{2}{3}\)
\(x.\left(\frac{3}{2}+2\right)-\frac{4}{5}=\frac{13}{15}\)
\(x.\frac{7}{2}=\frac{13}{15}+\frac{4}{5}\)
\(x.\frac{5}{2}=\frac{13}{15}+\frac{12}{15}\)
\(x.\frac{7}{2}=\frac{25}{15}=\frac{5}{3}\)
\(x=\frac{5}{3}:\frac{7}{2}\)
\(x=\frac{5}{3}.\frac{2}{7}=\frac{10}{21}\)
BA
30 tháng 9 2019
\(4^x=16^2\cdot32^4\)
\(4^x=4^4\cdot4^4\cdot8^4\)
\(4^x=128^4\)
\(4^x=2^{28}\)
\(x=28\)
2 tháng 4 2018
\(a)\) \(-\left(x+84\right)+213=-16\)
\(\Leftrightarrow\)\(-x-84+213=-16\)
\(\Leftrightarrow\)\(x=213-84+16\)
\(\Leftrightarrow\)\(x=145\)
Vậy \(x=145\)
\(b)\) \(\left(x-1\right)^2=\left|\frac{1}{4}-\frac{1}{2}-\frac{3}{4}\right|\)
\(\Leftrightarrow\)\(\left(x-1\right)^2=\left|-1\right|\)
\(\Leftrightarrow\)\(\left(x-1\right)^2=1\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x-1=1\\x-1=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=0\end{cases}}}\)
Vậy \(x=0\) hoặc \(x=2\)
Chúc bạn học tốt ~
NT
2 tháng 4 2018
a) \(-\left(x+84\right)+213=-16\)
\(-\left(x+84\right)=-16-213\)
\(-\left(x+84\right)=-229\)
\(\Rightarrow x+84=229\)
\(\Rightarrow x=229-84=145\)
Vậy \(x=145\)
b) \(\left(x-1\right)^2=\left|\frac{1}{4}-\frac{1}{2}-\frac{3}{4}\right|\)
\(\left(x-1\right)^2=\left|\frac{-1}{4}-\frac{3}{4}\right|\)
\(\left(x-1\right)^2=\left|-1\right|\)
\(\left(x-1\right)^2=1\)
\(\Rightarrow\orbr{\begin{cases}x-1=1\\x-1=-1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1+1=2\\x=-1+1=0\end{cases}}\)
Vậy \(x\in\left\{0;2\right\}\)
11 tháng 4 2019
\((2,7.x-1\frac{1}{2})\div\frac{2}{7}=\frac{-21}{4}\) \(3\frac{1}{3}.x+16\frac{3}{4}=-13.25\)
\(2,7.x-1\frac{1}{2}=-\frac{21}{4}\cdot\frac{2}{7}\) \(\frac{10}{3}.x+\frac{67}{4}=-13.25\)
\(2,7.x-\frac{3}{2}=-\frac{3}{2}\) \(\frac{10}{3}.x+\frac{67}{4}=-\frac{53}{4}\)
\(2,7.x=-\frac{3}{2}+\frac{3}{2}\) \(\frac{10}{3}.x=-\frac{53}{4}-\frac{67}{4}\)
\(2,7.x=0\) \(\frac{10}{3}.x=-30\)
\(x=0:2,7\) \(x=-30:\frac{10}{3}\)
\(x=0\) \(x=-9\)
Vậy x=0 Vậy x= -9
\(\left(4.5-2.x\right):\frac{3}{4}=1\frac{1}{3}\) \(1.5+1\frac{1}{4}.x=\frac{2}{3}\)
\(\left(4.5-2.x\right)=1\frac{1}{3}\cdot\frac{3}{4}\) \(1\frac{1}{4}.x=\frac{2}{3}-1.5\)
\(4.5-2.x=\frac{4}{3}\cdot\frac{3}{4}\) \(\frac{5}{4}.x=\frac{2}{3}-\frac{3}{2}\)
\(4.5-2.x=1\) \(\frac{5}{4}.x=-\frac{5}{6}\)
\(2.x=4.5-1\) \(x=-\frac{5}{6}:\frac{5}{4}\)
\(2.x=3.5\) \(x=-\frac{2}{3}\)
\(x=3.5:2\)
\(x=1.75\) Vậy \(x=-\frac{2}{3}\)
Vậy x=1.75