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\(\left(5^{19}\cdot5^{14}\right):5^{32}\)
\(=5^{19+14}:5^{32}\)
\(=5^{33}:5^{32}\)
\(=5^{33-32}\)
\(=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(A=\frac{19^{30}+5}{19^{31}+5}\Rightarrow19A=\frac{19.\left(19^{30}+5\right)}{19^{31}+5}=\frac{19^{31}+95}{19^{31}+5}=\frac{19^{31}+5+90}{19^{31}+5}=1+\frac{90}{19^{31}+5}\)
\(B=\frac{19^{31}+5}{19^{32}+5}\Rightarrow19B=\frac{19.\left(19^{31}+5\right)}{19^{32}+5}=\frac{19^{32}+95}{19^{32}+5}=\frac{19^{32}+5+90}{19^{32}+5}=1+\frac{90}{19^{32}+5}\)
Nên \(19A< 19B\Rightarrow A< B\)
Nhầm: Vì \(\frac{90}{19^{31}+5}>\frac{90}{19^{32}+5}\Rightarrow1+\frac{90}{19^{31}+5}>1+\frac{90}{19^{32}+5}\Rightarrow A>B\)
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a)74*(32+5)-32*(74+5)=74*32+74*5-32*74-32*5=(74*32-32*74)+(74*5-32*5)=0+(74-32)*5=42*5=210
b)-17*25+34*26-17*49=-17*25-(-17)*26*2-17*49=-17*25-(-17)*52+(-17)*49=(-17)*(25-52+49)=(-17)*22=-374
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a, 10 + 2x = 45 ÷ 43
10 + 2x = 45/43
2x = 45/43 - 10
2x = -385/43
x = -385/43 ÷ 2
x = -385/86
b, 2x - 138 = 23.32
2x - 138 = 736
2x = 736 + 138
2x = 874
x = 874 ÷ 2
x = 437
c, 231 - ( x - 6 ) = 1339 ÷ 13
231 - ( x - 6 ) = 103
x - 6 = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
d, x + 5.2 - ( 32 + 16.3 ÷ 6 - 15 ) = 0
x + 10 - 25 = 0
x + 10 = 0 + 25
x + 10 = 25
x = 25 - 10
x = 15
a) 10 + 2 . x = 45 : 43
2 . x = 45/43 -10
2 . x = -385/43
x = -385/43 : 2
x = -385/86
b) 2 . x - 138 = 23 . 32
2 . x - 138 = 736
2 . x = 736+138
2 . x = 874
x = 874 : 2
x = 437
c) 231 - (x -6) = 1339 : 13
231 - (x -6) = 103
x - 6 = 231 -103
x - 6 = 98
x = 98 +6
x = 104
d) x + 5 . 2 - (32 +16 . 3 : 6 - 15) = 0
x + 5 . 2 - (32 + 48 : 6 - 15) = 0
x + 5 . 2 - (32 + 8 - 15) = 0
x + 5 . 2 - 25 = 0
x + 10 - 25 = 0
x + 10 = 0 + 25
x + 10 = 25
x = 25 - 10
x = 15
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Ta sẽ so sánh : 3227 và 1839
Có 1839>1639=(24)39=2156
Lại có 3227=(25)27=2135
Vì 2135<2156 nên 3227<1839
=> -3227>-1839
3227 = 25 x 27 = 2135
1839 > 1639 = 24 x 39 = 2156
mà 2135 < 2156
=> -2135 > -2156
=> -3227 > -1839
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
6415 = (26)15 = 290
3218 = (25)18 = 290
Vì 290 = 290
=> 6415 = 3218
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Trả lời :
\(4^5=\left(2^2\right)^5=2^{2.5}=2^{10}\)
\(32^2=\left(2^5\right)^2=2^{5.2}=2^{10}\)
\(\Rightarrow4^5=32^5\)
Ta có 45 = (22)5 = 22.5 = 210
322 = (25)2 = 25.2 = 210
=> 45 = 322 (= 210)