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k) Ta có: \(\dfrac{7}{20}+\dfrac{3}{5}+\dfrac{-1}{4}\)
\(=\dfrac{7}{20}+\dfrac{15}{20}+\dfrac{-5}{20}\)
\(=\dfrac{7+15-5}{20}\)
\(=\dfrac{17}{20}\)
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Sorry nãy máy load chậm
\(\frac{-101}{-100}=\frac{101}{100}>1\)
\(\frac{200}{201}< 1\)
\(\Rightarrow\frac{200}{201}< \frac{101}{100}\Rightarrow\frac{200}{201}< \frac{-101}{-100}\)
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a, \(\left(-236\right).41+236.\left(-59\right)=\left(-236\right).\left(41+59\right)=\left(-236\right).100=-23600\)
b,\(138.\left(-125\right)-\left(-138\right).25=138.\left[\left(-125\right)-\left(-25\right)\right]=138.100=13800\)
c, \(\left(-271\right).\left(-159\right)+271.\left(-59\right)=271.\left[159+\left(-59\right)\right]=217.100=27100\)
d, \(129.\left(-73\right)+\left(-129\right).27=129.\left(-73-27\right)=129.\left(-100\right)=-12900\)
e, \(256.\left(-57\right)-\left(-256\right).\left(-43\right)=256.\left(-57-43\right)=256.\left(-100\right)=-25600\)
f, \(\left(-234\right).67+234.\left(-33\right)=234.\left(-67-33\right)=234.\left(-100\right)=-23400\)
ko cần chép đề nha
a. 236x(-41)+236x(-59)
=236x[(-41)+(-59)]
=236x(-100)
=-23600
b.-138x125-(-138)x25
=(-138)x(125-25)
=(-138)x100
=-13800
c.câu này mik giải thích là khi chuyển dấu "-" của -59 sang -271 thì -- sẽ biến thành +
c. 271x159+271x(-59)
=271x(159+(-59))
=271x100
=27100
d(-129)x73+(-129)x27
=(-129)x(73+27)
=(-129)x100
=-12900
e. (-256)x57-(-256)x(-43)
=(-256)x[57-(-43)]
=-256x100
=-25600
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\(7,MSC:315\\ \dfrac{2}{5}=\dfrac{2.63}{5.63}=\dfrac{126}{315}\\ \dfrac{13}{45}=\dfrac{13.7}{45.7}=\dfrac{91}{315}\\ \dfrac{-12}{35}=\dfrac{-12.9}{35.9}=\dfrac{-108}{315}\\ 8,MSC:102\\ \dfrac{4}{17}=\dfrac{4.6}{17.6}=\dfrac{24}{102}\\ \dfrac{8}{51}=\dfrac{8.2}{51.2}=\dfrac{16}{102}\\ \dfrac{3}{34}=\dfrac{3.3}{34.3}=\dfrac{9}{102}\)