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A = ab - ac + ad
= a(b - c + d)
B = ac + ad - bc - bd
= a(c + d) - b(c + d)
= (a - b)(c + d)
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ab-ac+ad
=a.(b-a+d)
b) ac+ad-bc-bd
=c.(a-b)+d(a-b)
=(a-b).(c+d)
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a) Ta có \(ab-ac+ad=a.\left(b-c+d\right)\)
b) Ta có \(ac+ad-bc-bd=a.\left(c+d\right)-b.\left(c+d\right)\)
\(=\left(c+d\right).\left(a-b\right)\)
a) ab - ac + ad
= a.b - a.c + a.d
= a.(b-c+d)
b) ac + ad - bc - bd
= a.c + a.d - b.c - b.d
= a.(c+d) - b.(c-d)
= a.(c-d) + b.(c-d)
= (a+b) . (c-d)
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a)ab−ac+dc−db=a(b+c)−d(b−c)=(b−c)(a−d)
b)ac+ad−bc−bd=a(c+d)−b(c+d)=(c+d)(a−b)
![](https://rs.olm.vn/images/avt/0.png?1311)
ab-ac+ad = a(b-c+d)
ac+ad-bc-bd = a(c+d)-b(c+d) =(a-b)(c+d)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ab - ac + ad = a(b - c + d)
b) ac + ad - bc - bd
= a(c + d) - b(c + d)
= (c + d) (a - b)
![](https://rs.olm.vn/images/avt/0.png?1311)
ab + ac = a(b + c)
ab - ac + ad = a(b - c + d)
ax - bx - cx + dx
=x(a - b - c + d)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)=a(b-c+d)
b)=a(c+d)-b(c-d)
=a(c+d)+b(c+d)
=(c+d).(a+b)
Tick nha