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a.\(x:308=509\)
\(x=509x308=156772\)
b.\(x+354=860-45\)
\(x+354=815\)
\(x=415-354=61\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1 :
a) 354 x 16 + 354 x 34
= 354 x ( 16 + 34 )
= 354 x 50
= 17700
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(124-x\right)\times354=354\times28\)
\(\left(124-x\right)=354\times28\div354\)
\(124-x=28\)
\(x=124-28\)
\(x=96\)
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1: =354(4+5+1)-350
=3540-350
=3190
2:
a: 19040:x=340
=>x=19040/340=56
b: x-3678=2541*4
=>x-3678=10164
=>x=10164+3678=13842
c: x*282-270*x=1512
=>12x=1512
=>x=126
d: =>(177-96+21):x=6
=>102:x=6
=>x=102/6=17
![](https://rs.olm.vn/images/avt/0.png?1311)
Theo đề bài: (X+3)+(X+7)+(X+11)+...........+(X+79)=860
X.20+(3+7+11+.........+79)=86
SSH: (79-3):4+1:2=10 (cặp)
SC:79+3=82
3+7+11+.....+79=10.82=820
X.20+820=860
X.20 =860-820=40
X =40:20
X =2
Đ/S;X=2
\(\left(x+3\right)+\left(x+7\right)+\left(x+11\right)+...+\left(x+79\right)=860\)
\(\Leftrightarrow20x+\left(3+7+11+...+79\right)=860\)
\(\Leftrightarrow20x+20.\frac{79+3}{2}=860\)
\(\Leftrightarrow20x+820=860\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(x+x+....+x)+(3+7+11+.....+79)=860
20x+820=860
20x=860-820
20x=40
x=40:20
x=2
Fan tf thì kb nha
![](https://rs.olm.vn/images/avt/0.png?1311)
(x + 3) + (x + 7) + (x + 11) + ... + (x + 79) = 860
=> x + 3 + x + 7 + x + 11 + ... + x + 79 = 860
=> (x + x + x + ... + x) + (3 + 7 + 11 + ... + 79) = 860
=> 20x + (79 + 3).20 : 2 = 860
=> 20x + 82.20 : 2 = 860
=> 20x + 82.10 = 860
=> 20x + 820 = 860
=> 20x = 40
=> x = 2
vậy_
#)Giải :
\(\left(x+3\right)+\left(x+7\right)+...+\left(x+79\right)=860\)
\(\left(x+x+...+x\right)+\left(3+7+...+79\right)=860\)(trong mỗi ngoặc có 20 số hạng)
\(x\times20+\frac{\left(79+3\right)\times20}{2}=860\)
\(x\times20+820=860\)
\(x\times20=860-820\)
\(x\times20=40\)
\(x=40\div20\)
\(x=2\)
b) X + 354 = 860 – 45
x+354-815
x=815-354
x=461
X + 354 = 860 - 45
x + 354 = 815
x = 815 - 354
x = 461
k mình nha