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a)A={3;4;5;6;7}
b) a có 5 phần tử
a)A={-2;-1;0;1;}
b)có 4 phần tử
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(M=\left\{x\inℕ|4x\le16\right\}\)
\(\Rightarrow M=\left\{x\inℕ|x\le4\right\}\)
\(\Rightarrow M=\left\{1;2;3;4\right\}\)
b) \(N=\left\{x\inℕ|15< 3x\le33\right\}\)
\(\Rightarrow N=\left\{x\inℕ|5< x\le11\right\}\)
\(\Rightarrow N=\left\{6;7;8;9;10;11\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(M=\left\{x\in N|4x\le16\right\}\)
\(\Rightarrow4x\le16\)
\(\Rightarrow x\le4\)
Mà: \(x\in N\Rightarrow x\ge0\)
\(\Rightarrow M=\left\{0;1;2;3;4\right\}\)
b) Ta có: \(N=\left\{x\in N|15< 3x\le33\right\}\)
\(\Rightarrow15< 3x\le33\)
\(\Rightarrow\dfrac{15}{3}< x\le\dfrac{33}{3}\)
\(\Rightarrow5< x\le11\)
\(\Rightarrow N=\left\{6;7;8;9;10;11\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{N}{2}×x-4=20\)
\(\Rightarrow20:2+4\)
\(=14\)
\(\Rightarrow B=\left\{14\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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