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Nếu câu hỏi là phân tích đa thức thành nhân tử:
\(7x^2-14xy^2-7y^4=7\left(x^2-2xy^2-\left(y^2\right)^2\right)=7\left(x-y^2\right)^2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
c: \(x^2-4x^2y^2+y^2+2xy\)
\(=\left(x+y\right)^2-\left(2xy\right)^2\)
\(=\left(x+y+2xy\right)\left(x+y-2xy\right)\)
d: \(7x^2-14xy^2+7y^4\)
\(=7\left(x^2-2xy^2+y^4\right)\)
\(=7\left(x-y^2\right)^2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Phan h da thuc thanh nhan tu a ban ?
Ta co
7x2-14xy+7y2
=7(x2-2xy+y2)
=7(x-y)2
Ta có:\(7x^2-14xy+7y^2\)
\(=7\left(x^2-2xy+y^2\right)\)
\(=7\left(x^2-2.x.y+y^2\right)\)
\(=7\left(x-y\right)^2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(5a\left(x-3y\right)+8\left(3y-x\right)\)
\(=5a\left(x-3y\right)-8\left(x-3y\right)\)
\(=\left(x-3y\right)\left(5a-8\right)\)
b) \(7x^2-14xy+7y^2-7z^2\)
\(=7\left(x^2-2xy+y^2-z^2\right)\)
\(=7\left[\left(x^2-2xy+y^2\right)-z^2\right]\)
\(=7\left[\left(x-y\right)^2-z^2\right]\)
\(=7\left(x-y-z\right)\left(x-y+z\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
c) \(\left(x^2-x+6\right)^2+\left(x-3\right)^2\)
\(=-\left(\left(x^2+x-6\right)-\left(x+3\right)^2\right)\)
\(=-\left(x^2+x-6-x-3\right)\left(x^2+x+6+x+3\right)\)
\(=-\left(x^2-9\right)\left(x^2+2x+9\right)\)
\(=-\left(\left(x-9\right)\left(x+9\right)\left(x^2+2x+9\right)\right)\)
a) 7x2 - 14xy + 7y2
= 7(x2 - 2xy + y2)
= 7(x - y)2
b) x2 + 3x - 10
= - ( x2 - 3x + 10 )
= - ( x2 - 2 . 3/2x + 9/4 + 31/4 )
= - (( x - 3/2 )2 + 31/4
= (x - 3/2)2 - \(\left(\sqrt{\frac{31}{4}}\right)^2\)
= \(\left(x-\frac{3}{2}-\sqrt{\frac{31}{4}}\right)\left(x-\frac{3}{2}+\sqrt{\frac{31}{4}}\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(4x^4-9x^2\)
\(=\left(2x^2\right)^2-\left(3x\right)^2\)
\(=\left(2x^2-3x\right)\left(2x^2+3x\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(7x^2-14xy^2+7y^4=7\left(x^2-2xy^2+y^4\right)=7\left(x-y^2\right)^2\)
\(7.\left(x^2-2.x.y^2+y^4\right)\) \(=7.\left(x-y^2\right)^2\)
\(x^2+4x+4-y^2\) \(=\left(x^2+2.x.2+2^2\right)-y^2\) \(=\left(x+2\right)^2-y^2\) \(\left(x+2+y\right)\left(x+2-y\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=7x\left(x+2y\right)-4\left(x+2y\right)=\left(7x-4\right)\left(x+2y\right)\)
7x2-14xy2+7y4=7(x2-2xy2+(y2)2) =7(x-y2)2